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There are four contestants in the competition for 6

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New post 18 Sep 2003, 14:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are four contestants in the competition for 6 different prizes. A contestant can win only one prize. How many different outcomes are possible at the competition for the four contestants?

A) 15

B) 30

C) 60

D) 180

E) 360
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New post 21 Sep 2003, 08:55
Is it A?

6*5*4*3/4! = 15
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New post 21 Sep 2003, 15:29
I think it's a permutation. I'd choose E.
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New post 03 Nov 2003, 11:06
I think the correct answer is D.

Just try to imagine putting 4 ppl into 6 seats. where the four ppl can choose any of the 6 seats.

So its 6P4...OR 180.


my 2 cents....
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New post 03 Nov 2003, 12:07
sudzpwc wrote:
I think the correct answer is D.

Just try to imagine putting 4 ppl into 6 seats. where the four ppl can choose any of the 6 seats.

So its 6P4...OR 180.


my 2 cents....


6P4 is = 360 (NOT 180) So the answer would be E.
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New post 03 Nov 2003, 13:34
am,
my bad...silly mistake in cacl....
thanks though.
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New post 14 Jan 2004, 19:48
I did it this way.
Assume we have to seat 4 people in 6 chairs.
so Chose 4 seats first = 6C4 = 15
then 4 people can seat in 4! ways
so total ways = 6C4 * 4! = 15*24 = 360
  [#permalink] 14 Jan 2004, 19:48
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There are four contestants in the competition for 6

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