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there are "n" dalmations having 101 spots each.Due to a

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there are "n" dalmations having 101 spots each.Due to a [#permalink] New post 11 Aug 2003, 20:54
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there are "n" dalmations having 101 spots each.Due to a disorder, one spot of each dalmation vanishes at the end of each day except on Sunday. If this disorder starts on Jan 1st, 1990(Monday) then at the end of which day of 1900 will the total no. of spots be "n"?
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 [#permalink] New post 13 Aug 2003, 08:36
It is an ambiguous question. "then at the end of which day of 1900 will the total no. of spots be "n"?"

the total number of what spots? the vanished or the remained?

the first case: n dogs lost one spot each by the end of Jan 1st, so next day we have total n lost spots.

the second case: we will have n spots remained when each dog will lose 100 spots, or 100n spots in total. Each day n dogs lose n spots, so the whole process will take 100 'working' days.

100/6= 16 six-day periods +4 days

All days will be (16+1)*6+4=106 days

January has 31 days
February has 28 days (not a leap year!)
March has 31
------------90 days
April 16th (Tuesday) is the date. By the end of this day, all dogs will have n spots left.
  [#permalink] 13 Aug 2003, 08:36
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there are "n" dalmations having 101 spots each.Due to a

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