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Manager
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There are ten glasses: 5 red, 3 blue and 2 green. Two [#permalink]
 19 Aug 2003, 10:50
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There are ten glasses: 5 red, 3 blue and 2 green. Two glasses are taken without repetition. How many combinations are there, so that both glasses are of different color.
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Manager
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Total Combinations = 10C2 = 45
Both Red = 5C2 = 10
Both Blue = 3C2 = 3
Both Green = 2C2 = 1
45 - 10 - 3 - 1 = 31
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Manager
Joined: 14 Aug 2003
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another way would be:
5c1*3c1+3c1*2c1+5c1*2c1=15+6+10=31
cheers, j
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