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There are three workers , Peter, Jamie, Vicky that can paint

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Manager
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There are three workers , Peter, Jamie, Vicky that can paint [#permalink]

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27 Nov 2006, 11:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are three workers , Peter, Jamie, Vicky that can paint a room in 8, 6, 3 hours respectively, what is the ratio of the amount of work done by the slowest worker painting the room to the total amount of work?
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27 Nov 2006, 11:10
Must be 1/5.

The slowest worker's work done:1/8
Total work done: 1/8+1/6+1/3=45/72

ratio: (1/8)/(45/72)=(1/8)*(72/45)=1/5
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27 Nov 2006, 11:16
I think it's 1/5.

The slowest worker is Peter with 8 hrs. thus, in 1 hr, he 's done 1/8 of the job.
Calculating the total amt of work done together in 1 hr: 1/8+1/6+1/3 = 30/48. and together, it will take them 1.6 hrs.

Thus, the portion that peter will get done himself is (1/8)*1.6 and 1/5 of the total work done
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Re: work problem [#permalink]

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27 Nov 2006, 14:51
There are three workers , Peter, Jamie, Vicky that can paint a room in 8, 6, 3 hours respectively, what is the ratio of the amount of work done by the slowest worker painting the room to the total amount of work?

Togather in 1 hr (1/8)+(1/6)+(1/3)=30/48

in 1 hour slowest does 1/8

(1/8)/(30/48)=1*48/(8*30)=6/30=1/5=20%
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28 Nov 2006, 16:32
At any given time the amount of work done by each of the workers is given by 1/8:1/6:1/3

Common denominator = 24 -----> 3/24:4/24:6/24

Slowest worker does 3/24 of work

Total work = 15/24

Ratio of slowest:total work = (3/24)/(15/24) or (3/24)*(24/15)

Cancelling out 24 gives 3/15 or 1/5
28 Nov 2006, 16:32
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There are three workers , Peter, Jamie, Vicky that can paint

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