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There are two right circular cylinders, A and B. The

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There are two right circular cylinders, A and B. The [#permalink] New post 09 Feb 2007, 22:29
There are two right circular cylinders, A and B. The diameter of the base of the cylinder A is twice that of the base of the cylinder B. The height of the cylinder A is half that of the cylinder B. If the radius and the height of the cylinder B are r and h, respectively, what is the absolute value of the difference of the surface areas between the cylinder A and the cylinder B?

A: 4pi r^2
B: 6pi r^2
C: 8pi r^2
D: 10pi r^2
E: 14pi r^2



OA: B
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 [#permalink] New post 09 Feb 2007, 23:14
B (the 2pi*r*d will get cancelled, we have two circular parts 2*(pi*4r^2 - pi*r^2) = 6*pi*r^2
  [#permalink] 09 Feb 2007, 23:14
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There are two right circular cylinders, A and B. The

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