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You should be able to see that you cannot answer this question given the information in the question. Perhaps a more suitable question is:
Given the above information, what is the minimum number of people that own all 5 cars? _________________
Best,
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993
I was able to get 1 but due to unavailibility of net was not able to post it. My hard Luck!!!!!!
Well to explain it is a bit difficult. But the way i that i found out the total as 401. So i thought that lets all have 4 cars. So we are remaining with 1. Hence atleast 1 person need to have more then 4 cars or all the 5 cars.
Initially i thought that its not logically correct but if you reframe it to 3 cars and 10 persons ans then on a paper draw all the combinations u will know that it works!!!!!!!!
Okay. Everyone seems to be focusing on "1" as the answer. Let's apply a sanity check.
Lets says that 62 people own all five cars. Of the 38 remaining people. 10 own BMV, 7 own Ferrari, and 21 own both. Now everyone has at least one car. We can divide up the remainder Porsches and AMs among those 38 people any way we want since there are no Lamborghinis left.
Hence, given the infomation in the question, IT IS POSSIBLE for as many as 62 people to own all of the cars.
So why is the answer "1"?
I still maintain that the question must be reworded. _________________
Best,
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993
You should be able to see that you cannot answer this question given the information in the question. Perhaps a more suitable question is:
Given the above information, what is the minimum number of people that own all 5 cars?
This question seems difficult because setting up a Venn diagram is impossible with more than 3 variable (unless you are one of those freaky math or physics majors that think in 4 and 5-D space-time)
Assuming that the question is reworded as above, here is a simple step by step way to get to the solution:
There are 93 beamers and 90 ferraris. Hence, there are at a minimum 93+90-100 or 83 people with both cars. Agree? (you can set up a venn diagram and come up with this equation quite easily -- leave that as an exercise).
There are at a minimum 83 people with BMW and Ferr and 81 Porsche drivers. Hence there are at a minimum 83 - 81 - 100 or 64 people who drive all 3 cars.
There are at a minimum 64 owning B, F, and P. There are 75 people driving AMs, hence there are at a minimum 64 + 75 - 100 or 39 people driving B,F, P, and AM.
There are at least 39 people driving B,F,P, and AM and 62 people driving Ls. Hence there are at least 62+39-100 = 1 person driving all 5 cars.
QED _________________
Best,
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993
Akamai, if the question is reworded then i think my appraoch is absolutely correct.Infact i solved this by assuming that we need to find the minimum number of person.