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there is a series T,T2,T3..................Tn where [#permalink]
 26 Aug 2003, 04:43
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there is a series T,T2,T3..................Tn
where Tn+1=Tn/2, what is the value of T5?
1) T4= some value(can't remember)..Let's say 5
2)T1- T5=15/16
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I think (E) since we do not know the number of integers in the set and there is no indication that T3-T2=T4-T3 etc. (i.e. there are equal intervals between integers T1,T2...Tn)
Hey, p_malh, what's the answer 
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From (1), T5 = (1/2) T4 = (1/2) 5
From (2) T5 = T1 - 15/16
==> (1/16) T1 = T1- 15/16
==> T1 = 1 and T5 = 1/6
So D
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Hey guys........
I don't know the answer....I got confused b/w D and E
for stmt 2, I didn't know how to solve for T1, since T1 would be
T0+1=T0/2
and we don't know what T0 is???
anybody???
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Brainless wrote: From (1), T5 = (1/2) T4 = (1/2) 5
From (2) T5 = T1 - 15/16
==> (1/16) T1 = T1- 15/16
==> T1 = 1 and T5 = 1/6
So D
Hey Brainless.......
How did you work the Bold part?
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Manager
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p_malh wrote: Brainless wrote: From (1), T5 = (1/2) T4 = (1/2) 5
From (2) T5 = T1 - 15/16
==> (1/16) T1 = T1- 15/16
==> T1 = 1 and T5 = 1/6
So D Hey Brainless....... How did you work the Bold part? T5 = 1/2 T4 = 1/2(1/2(T3)) = 1/2(1/2(1/2T2))) = 1/2(1/2(1/2(1/2T1)))) --- per definitionof the series
which is 1/16 of T1 ..
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