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there is a series T,T2,T3..................Tn where

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there is a series T,T2,T3..................Tn where [#permalink] New post 26 Aug 2003, 03:43
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A
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C
D
E

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there is a series T,T2,T3..................Tn

where Tn+1=Tn/2, what is the value of T5?

1) T4= some value(can't remember)..Let's say 5

2)T1- T5=15/16
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 [#permalink] New post 26 Aug 2003, 05:24
I think (E) since we do not know the number of integers in the set and there is no indication that T3-T2=T4-T3 etc. (i.e. there are equal intervals between integers T1,T2...Tn)

Hey, p_malh, what's the answer :)
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 [#permalink] New post 26 Aug 2003, 06:15
From (1), T5 = (1/2) T4 = (1/2) 5

From (2) T5 = T1 - 15/16
==> (1/16) T1 = T1- 15/16

==> T1 = 1 and T5 = 1/6

So D
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 [#permalink] New post 26 Aug 2003, 06:38
Hey guys........


I don't know the answer....I got confused b/w D and E

for stmt 2, I didn't know how to solve for T1, since T1 would be

T0+1=T0/2

and we don't know what T0 is???

anybody???
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 [#permalink] New post 26 Aug 2003, 12:25
Brainless wrote:
From (1), T5 = (1/2) T4 = (1/2) 5

From (2) T5 = T1 - 15/16
==> (1/16) T1 = T1- 15/16
==> T1 = 1 and T5 = 1/6

So D



Hey Brainless.......

How did you work the Bold part?
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 [#permalink] New post 26 Aug 2003, 18:35
p_malh wrote:
Brainless wrote:
From (1), T5 = (1/2) T4 = (1/2) 5

From (2) T5 = T1 - 15/16
==> (1/16) T1 = T1- 15/16
==> T1 = 1 and T5 = 1/6

So D



Hey Brainless.......

How did you work the Bold part?


T5 = 1/2 T4 = 1/2(1/2(T3)) = 1/2(1/2(1/2T2))) = 1/2(1/2(1/2(1/2T1)))) --- per definitionof the series

which is 1/16 of T1 ..
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  [#permalink] 26 Aug 2003, 18:35
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there is a series T,T2,T3..................Tn where

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