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# There is a tank where certain fluid is stored. The tank is

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There is a tank where certain fluid is stored. The tank is [#permalink]

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19 May 2003, 23:07
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There is a tank where certain fluid is stored. The tank is full. There are five guys who take half of what is stored. The first guy takes half, the second takes half a remainder, and so on.

How much fluid in terms of the initial quantity will they take away?
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19 May 2003, 23:23
correct
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08 Jan 2006, 02:58
How did you get that??

How is it possible-- that if only half of the tank liquid was taken initially by the 5 guys....how can they take more than 1/2?

Please some one explain. I'm getting a totally different answer and think i'm right!!
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08 Jan 2006, 03:05
stolyar wrote:
There is a tank where certain fluid is stored. The tank is full. There are five guys who take half of what is stored. The first guy takes half, the second takes half a remainder, and so on.

How much fluid in terms of the initial quantity will they take away?

I don't know if stolyar made the question by himself, but it's ambiguous.

What the question should look like:

There is a tank in which a certain fluid is stored. The tank is full. If there are five guys who take an amount of fluid out of the tank, whereas the first one takes out half of the entire amount, the second one half of the remainder etc., how much fluid will be left in the tank?

1-0,5^5= 31/32
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08 Jan 2006, 05:31
vizzz wrote:
How did you get that??

How is it possible-- that if only half of the tank liquid was taken initially by the 5 guys....how can they take more than 1/2?

Please some one explain. I'm getting a totally different answer and think i'm right!!

Guy1: Before taking = 1 . Taken = 1/2
Guy2: Before taking = 1/2 . Taken = 1/4
Guy3: Before taking = 1/4 . Taken = 1/8
Guy4: Before taking = 1/8 . Taken = 1/16
Guy5: Before taking = 1/16 . Taken = 1/32 Now left is 1/32

Total taken by all = 1-(1/32) = 31/32
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08 Jan 2006, 05:36
I don't know if stolyar made the question by himself, but it's ambiguous.

What the question should look like:

There is a tank in which a certain fluid is stored. The tank is full. If there are five guys who take an amount of fluid out of the tank, whereas the first one takes out half of the entire amount, the second one half of the remainder etc., how much fluid will be left in the tank?

1-0,5^5= 31/32

So basically-- if they are asking how much fluid will be left in the tank, the answer should be 1- 31/32 since the 5 guys have taken 31/32 of the liquid in the tank.

So answer should be 1/32 of the liquid is left in the tank. Is that correct or am i interpreting the question incorrectly.
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08 Jan 2006, 06:03
@vizz

Each guy takes out the half of the remainder.

En bref: 1/2 is left after the first guy has done ...

1-(1/2)^5
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08 Jan 2006, 11:51
ps_dahiya wrote:
vizzz wrote:
How did you get that??

How is it possible-- that if only half of the tank liquid was taken initially by the 5 guys....how can they take more than 1/2?

Please some one explain. I'm getting a totally different answer and think i'm right!!

Guy1: Before taking = 1 . Taken = 1/2
Guy2: Before taking = 1/2 . Taken = 1/4
Guy3: Before taking = 1/4 . Taken = 1/8
Guy4: Before taking = 1/8 . Taken = 1/16
Guy5: Before taking = 1/16 . Taken = 1/32 Now left is 1/32

Total taken by all = 1-(1/32) = 31/32

man !!!!!!!.....I forgot to minus 1/32 from 1 !!!!!!!1

Great job ps_dahiya
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