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# There is a type of fruit. Before drying, 99% of it is water.

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Manager
Joined: 20 Sep 2004
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There is a type of fruit. Before drying, 99% of it is water. [#permalink]  15 Dec 2004, 21:14
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0% (00:00) correct 0% (00:00) wrong based on 1 sessions
There is a type of fruit. Before drying, 99% of it is water. After drying, the water takes up 98%. Its original weight is 100, what is the weight after drying?
Intern
Joined: 26 Nov 2004
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Before drying 99(water) + 1(whatever)= 100
After drying 98(water) + 1(whatever) = 99.

I think it works out.
Manager
Joined: 15 Jul 2004
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PS: percentage [#permalink]  16 Dec 2004, 05:34
Original fruit: 100 weight units (WU) = 99 WU of water + 1 WU of â€œdry residueâ€

Last edited by artabro on 16 Dec 2004, 06:06, edited 1 time in total.
Director
Joined: 07 Nov 2004
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Total wt of fruit = 100 units
Wt of water = 99 units
Wt of fruit matter = 1 unit

After evaporation there is 98% of water and 2% of fruit matter. Let the new wt of fruit be "x"

(2/100) * x = 1 unit (Assuming that only the water evaporates, the wt of fruit matter remains the same)

x = 100/2 = 50 units = Final wt of fruit after evaporation.
Manager
Joined: 28 Jul 2004
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Gayathri,

You are using proportion as I see.But this concept does not work for Wt of water.This is why:
(98/100) * x = 99
x = 99 * (100/98)
= 99 * (50/49)
++++

The answer for the above is not = 50units.Am I missing something?Tx.

Anna

gayathri wrote:
Total wt of fruit = 100 units
Wt of water = 99 units
Wt of fruit matter = 1 unit

After evaporation there is 98% of water and 2% of fruit matter. Let the new wt of fruit be "x"

(2/100) * x = 1 unit (Assuming that only the water evaporates, the wt of fruit matter remains the same)

x = 100/2 = 50 units = Final wt of fruit after evaporation.

_________________

We can crack the exam together

Director
Joined: 07 Nov 2004
Posts: 695
Followers: 4

Kudos [?]: 22 [0], given: 0

Anna Rama wrote:
Gayathri,

You are using proportion as I see.But this concept does not work for Wt of water.This is why:
(98/100) * x = 99
x = 99 * (100/98)
= 99 * (50/49)
++++

The answer for the above is not = 50units.Am I missing something?Tx.

Anna

Anna,

I am not sure I understand your question. This is the way I looked at the problem. The wt of fruit matter in the fruit does not change but the water content changes in the fruit thus altering the wt of fruit.

Also, I interpreted the problem as the wt of fruit is 100 units with 99 units of water and 1 unit of fruit matter. After the fruit has dryed and some of portion of the water has evaporated, the new ratio of wt of water to wt of fruit matter is 98%:2%. Since I have assumed that the wt of fruit matter does not change, the 2% of the new weight corresponds to 1 unit of fruit.
ie 2% of new wt = 1unit. So new wt = 1*100/2 =50.

Does that make sense? Let me know if I addressed your question...
Intern
Joined: 30 Oct 2004
Posts: 9
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Anna Rama wrote:
Gayathri,

You are using proportion as I see.But this concept does not work for Wt of water.This is why:
(98/100) * x = 99
x = 99 * (100/98)
= 99 * (50/49)
++++

The answer for the above is not = 50units.Am I missing something?Tx.

Anna

gayathri wrote:
Total wt of fruit = 100 units
Wt of water = 99 units
Wt of fruit matter = 1 unit

After evaporation there is 98% of water and 2% of fruit matter. Let the new wt of fruit be "x"

(2/100) * x = 1 unit (Assuming that only the water evaporates, the wt of fruit matter remains the same)

x = 100/2 = 50 units = Final wt of fruit after evaporation.

Fruit residue remains same:
Fruite weight = 100
In that 99% is water. Water weight = 99. Residue = 1
After drying, let the fruit weight = x units
x = 0.98x + 1. Hence x=50

There is a flaw in Anna Rama's explanation. (98/100) * x = 99 is not correct. 98% of x = 99 - amount of water evaporated.
Hence they are not same
Manager
Joined: 28 Jul 2004
Posts: 59
Location: Na
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Kudos [?]: 0 [0], given: 0

Thank you for your response.Now,I know where I missed.Tx.

Anna
_________________

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