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There were 36,000 hardback copies of a certain novel sold

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There were 36,000 hardback copies of a certain novel sold [#permalink] New post 04 Mar 2008, 22:22
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16. There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45,000
(B) 360,000
(C) 364,500
(D) 392,000
(E) 396,900

Pls help!
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 04 Mar 2008, 22:51
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jimmylow wrote:
16. There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45,000
(B) 360,000
(C) 364,500
(D) 392,000
(E) 396,900

Pls help!


p = 9h
p + h = 441,000
h + 9h = 441,000
10 h = 441,000
h = 44,100

p = t - h
p = 441,000 - 44,100
p = 396,900

E.
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 05 Mar 2008, 00:19
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GMAT TIGER wrote:
9 times as many paperback copies as hardback copies were sold


Friends, The discription above means that 9p =h or 9h=p? I meet some discription when I solve problem. Can you confirm that?

Thanks
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 06 Mar 2008, 09:18
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This problem I solved yesterday so it's fresh in my mind.
The correct answer is C.
The problem says that 36000 hardback copies were sold before paperback was issued.
Total copies sold = 441000
Total copies sold after the paperback was issued = 441000-36000=405000
p=9h
p+h = 405000
from here P= 364500
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 20 Feb 2010, 07:44
jimmylow wrote:
16. There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45,000
(B) 360,000
(C) 364,500
(D) 392,000
(E) 396,900

Pls help!


441000 = 36000 + 9x + x
x= 40500

Paperback Copies = 9x = 364500 hence C.
Whats the OA?
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 01 Mar 2011, 11:50
The question says a total of 441,000 copies of the novel were sold. I am assuming it includes both the initial 36,000 hardback and the paperback, which were later published. So why are we subtracting 36,000 from it? By subtracting 36,000, the equation X + Y = 441,000 would be invalid, (where X stands for the number of hardback sold and Y stands for the number of paperbacks sold), since X and Y are representing the total number of copies of each kind sold.

OA please.
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 01 Mar 2011, 12:07
Hardback copies sold before paperback version = 36000

Let hardback copies sold AFTER the paperback version, be x (because hardback copies were sold even after the paperback version)
Paperback sold, of course after the paperback version, = 9x

Total copies sold = 36000(hardback before paperback version) + x(hardback AFTER paperback version) + 9x(Paperback) = 441000

36000 + 10x = 441000
10x = 405000
x = 40500

Paperback copies = 9x = 40500 * 9 = 364500

Ans: "C"

Sorry; don't know the OA.
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Re: 1000PS: Section 1 Question 16 [#permalink] New post 14 Jun 2011, 22:27
p=9h is the key here.
p+h = 441,000

10h = 441,000
h=44100

p= 441,000-44100 = 364,500
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Re: 1000PS: Section 1 Question 16   [#permalink] 14 Jun 2011, 22:27
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