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There were initially no black marbles in a jar. Subsequently [#permalink]
 06 Feb 2008, 00:29
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There were initially no black marbles in a jar. Subsequently, new marbles were added to the jar. If marbles are drawn at random and selected marbles are not returned to the jar, what is the probability of selecting 2 black marbles in a row? (1) After the new marbles are added, 50% of all marbles are black. (2) Among the 10 added marbles, 8 are black.
Last edited by Bunuel on 29 Nov 2012, 04:11, edited 1 time in total.
Renamed the topic and edited the question.
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Re: probability ds [#permalink]
06 Feb 2008, 01:18
marcodonzelli wrote: There were initially no black marbles in a jar. Subsequently, new marbles were added to the jar. If marbles are drawn at random and the selected marbles are not returned to the jar, what is the probability of selecting 2 black marbles in a row?
1.after the new marbles are added, 50% of all marbles are black
2. among the 10 aded marbles, 8 are black (C) 1) Could have 3 black and 3 white or 8 black and 8 white. Probability differs for both cases. Insufficient 2) Need to know how many white are there in the jar. This doesn't provide that information. 1) & 2) combined There are 8 black and 8 white in the jar. Now it should be easy! Sufficient
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Re: probability ds [#permalink]
06 Feb 2008, 01:21
marcodonzelli wrote: There were initially no black marbles in a jar. Subsequently, new marbles were added to the jar. If marbles are drawn at random and the selected marbles are not returned to the jar, what is the probability of selecting 2 black marbles in a row?
1.after the new marbles are added, 50% of all marbles are black
2. among the 10 aded marbles, 8 are black 1: INsuff. we dont know how many marbles were added. 2: Insuff. All we knwo is that 10 marbles were added to an amount of marbles. 8 of these new marbles are black. Together, we know there must be a total of 16marbles. b/c 8 marbles = 1/2 of the entire jar. so 8/16*7/15 C.
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Re: probability ds [#permalink]
28 Nov 2012, 07:54
marcodonzelli wrote: There were initially no black marbles in a jar. Subsequently, new marbles were added to the jar. If marbles are drawn at random and the selected marbles are not returned to the jar, what is the probability of selecting 2 black marbles in a row?
1.after the new marbles are added, 50% of all marbles are black
2. among the 10 aded marbles, 8 are black Kindly correct me where am I wrong ? For me it should be D 1. No. of ways of selecting 1st & 2nd black marble : (3 black & 3 other) 3/6 * 2/5 ----- (45 black & 45 other) 45/90 * 44/89 ----- (1755 black & 1755 other) 1755/3510 * 1754/3509 ---- In all cases (P) = 0.5 * 0.4(approx. to 1st place decimal) ... suff. 2. No. of ways of selecting 1st & 2nd black marble : 8/10 * 7/9 = 28/45 ----- its very clearly specified that total marbles are 10 & 8 out of them are black ... suff.
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Re: probability ds [#permalink]
28 Nov 2012, 08:20
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himanshuhpr wrote: Kindly correct me where am I wrong ?
For me it should be D
1. No. of ways of selecting 1st & 2nd black marble : (3 black & 3 other) 3/6 * 2/5 ----- (45 black & 45 other) 45/90 * 44/89 ----- (1755 black & 1755 other) 1755/3510 * 1754/3509 ----
In all cases (P) = 0.5 * 0.4(approx. to 1st place decimal) ... suff.
2. No. of ways of selecting 1st & 2nd black marble : 8/10 * 7/9 = 28/45 ----- its very clearly specified that total marbles are 10 & 8 out of them are black ... suff. In statement 1, your calculation in getting 0.4 is incorrect. Infact in your example 1754/3509 would be very very close to 0.5 itself. Basically this value could range from 0 to 0.5. In statement 2, total is not 10. 10 is only number of total marbles added. You still dont know how many were already present. As shown by others earlier, choice C is the correct one.
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Re: probability ds [#permalink]
28 Nov 2012, 08:50
Vips0000 wrote: In statement 1, your calculation in getting 0.4 is incorrect. Infact in your example 1754/3509 would be very very close to 0.5 itself. Basically this value could range from 0 to 0.5.
In statement 2, total is not 10. 10 is only number of total marbles added. You still dont know how many were already present.
As shown by others earlier, choice C is the correct one. Thanks for your reply Vips , I concede that B and A( Especially when total balls have lower values 2,4 --- the values do diverge beyond 0.4) are not sufficient..... but would you hold A not sufficient even if after the new balls are added , the total balls becomes 52 or greater ???
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Re: probability ds [#permalink]
28 Nov 2012, 08:58
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himanshuhpr wrote: Vips0000 wrote: In statement 1, your calculation in getting 0.4 is incorrect. Infact in your example 1754/3509 would be very very close to 0.5 itself. Basically this value could range from 0 to 0.5.
In statement 2, total is not 10. 10 is only number of total marbles added. You still dont know how many were already present.
As shown by others earlier, choice C is the correct one. Thanks for your reply Vips , I concede that B and A( Especially when total balls have lower values 2,4 --- the values do diverge beyond 0.4) are not sufficient..... but would you hold A not sufficient even if after the new balls are added , the total balls becomes 52 or greater ??? Thats right. Even if number of balls is 500 or 600, the probability of such event would be different (though very close to each other). As long as you are getting multiple values instead of one unique solution (for the question asked - it could be a range asked in question) from a statement, just mark the option as insufficient.
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Re: probability ds [#permalink]
29 Nov 2012, 04:20
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himanshuhpr wrote: marcodonzelli wrote: There were initially no black marbles in a jar. Subsequently, new marbles were added to the jar. If marbles are drawn at random and the selected marbles are not returned to the jar, what is the probability of selecting 2 black marbles in a row?
1.after the new marbles are added, 50% of all marbles are black
2. among the 10 aded marbles, 8 are black Kindly correct me where am I wrong ? For me it should be D 1. No. of ways of selecting 1st & 2nd black marble : (3 black & 3 other) 3/6 * 2/5 ----- (45 black & 45 other) 45/90 * 44/89 ----- (1755 black & 1755 other) 1755/3510 * 1754/3509 ---- In all cases (P) = 0.5 * 0.4(approx. to 1st place decimal) ... suff. 2. No. of ways of selecting 1st & 2nd black marble : 8/10 * 7/9 = 28/45 ----- its very clearly specified that total marbles are 10 & 8 out of them are black ... suff. You could consider easier cases for (1). If after the new marbles are added, there is 1 black marble and 1 non-black marble in the jar (so if initially there was only 1 non-black marble and 1 black marble was added), then the probability of selecting 2 black marbles in a row will be 0 (since we have only 1 black marble). But if after the new marbles are added, there are 2 black and 2 non-black marbles in the jar, then the probability of selecting 2 black marbles in a row will obviously be more than 0. Hope it's clear.
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Re: There were initially no black marbles in a jar. Subsequently [#permalink]
31 Dec 2012, 04:02
P ( 1 & 2 Black ) = P ( first black ) * P ( second black ) = ?
model of jar > Black + Others = Total
P ( first b ) = b/t
after selecting one marble and throwing it away, the model will change and total num of marbles will be reduced by one, so ...
P (second black) = (b-1)/(t-1)
stmt 1. B = 50% * T
P( first black ) = b/t = 0.5
but we dont know t and b to find P ( sec b )
insuf.
stmt 2. new barles = 10 , 8 are black
no info about Total
insuf.
stmat 1+2 :
b = 0.5 t = 8
t = 16
P = 0.5 * [(8-1)/(16-1)]
ans : C
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Re: There were initially no black marbles in a jar. Subsequently
[#permalink]
31 Dec 2012, 04:02
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