Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 26 Oct 2016, 03:04

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# There will be problems that will require you really know how

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Eternal Intern
Joined: 07 Jun 2003
Posts: 467
Location: Lone Star State
Followers: 1

Kudos [?]: 137 [0], given: 0

There will be problems that will require you really know how [#permalink]

### Show Tags

05 Aug 2003, 14:01
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There will be problems that will require you really know how to manipulate algebra. Don't make the mistake I did and rely on picking numbers like I did for the SAT.

When 2/9 of the certain votes have been counted, 3/4 of those counted are in favor of the resolution. What fraction of the remaining votes must be against the resolution so that the total count will result in a vote of 2 to 1 against the resolution?

This is extremely challenging not to pick in numbers.

Victor
_________________

Ride em cowboy

Manager
Joined: 22 Jul 2003
Posts: 62
Location: CA
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

05 Aug 2003, 14:13
11/14

Let the total # of voters be 36x

Already counted = 36x * 2/9 = 8x
Out of which,
For the resolution = 8x*3/4 = 6x
So, already counted and against = 8x-6x=2x

Counting left for 36x - 8x = 28x votes
Let, the "for" candidate gets y votes out of the 28x
So, "against" gets 28x-y

"For" gets in total = 6x+y
"Against" gets = 2x+28x-y=30x-y

Given, (30x-y)/(6x+y)=2
=> y=6x

So, the "against" party has to get 28x-y=28x-6x=22x out of the remaining 28x votes. So, ratio = 22/28 = 11/14
Eternal Intern
Joined: 07 Jun 2003
Posts: 467
Location: Lone Star State
Followers: 1

Kudos [?]: 137 [0], given: 0

### Show Tags

05 Aug 2003, 15:51
I find it easier to do it the other way;
3 + x
------- = 1/2
1 + 14 -x

I don't know what "X" stands for your in your problem. Mine is votes.

VT
_________________

Ride em cowboy

Intern
Joined: 31 May 2003
Posts: 21
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

05 Aug 2003, 22:25
If all votes are either against or for the resolution, then the answer should be 33/42.
SVP
Joined: 30 Oct 2003
Posts: 1793
Location: NewJersey USA
Followers: 5

Kudos [?]: 97 [0], given: 0

### Show Tags

21 Jan 2004, 22:35
Let 36 be total votes

Counted = 36 * 2/9 = 8 votes
F = 8*3/4 = 6
A = 8-6 = 2

Remaining votes = 28
left f be for votes of this remaining 28 votes
total F = f+6
total against = 2+28-f = 30-f

now (30-f)/(f+6) = 2/1
30-f = 2f+12
3f = 18 or f = 6
so 22 out of 28 must be against
22/28 = 11/14
[#permalink] 21 Jan 2004, 22:35
Display posts from previous: Sort by

# There will be problems that will require you really know how

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.