metallicafan wrote:

This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!

Is x>y?

(1) x = y + 2

(2) x/2 = y -1

Is \(x>y\)?

(1) \(x=y+2\) --> if you just read what is written you'll get "\(x\) is 2 more than \(y\)", so \(x\) is more than \(y\). Sufficient.

Or you can substitute \(x\) in the question: is \(x>y\)? --> question becomes: is \(y+2>y\)? is \(2>0\)? YES, 2 is more than 0. So the answer to the question is YES. Sufficient.

(2) \(\frac{x}{2}=y-1\) --> \(x=2y-2\) --> substitute \(x\) in the question: is \(x>y\)? --> question becomes: is \(2y-2>y\)? is \(y>2\)? We don't know that, hence this statement is not sufficient.

As for number plugging:

On DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.Try \(x=0\) then \(y=1\) and the answer to the question is NO;

Increase \(x\): try \(x=10\) then \(y=6\) and the answer to the question is YES.

Two different answer, hence not sufficient.

Answer: A.

Hope it helps.