Find all School-related info fast with the new School-Specific MBA Forum

It is currently 29 Aug 2014, 06:40

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

This is one of Akamai's .. nice one...

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
CEO
CEO
avatar
Joined: 15 Aug 2003
Posts: 3470
Followers: 60

Kudos [?]: 665 [0], given: 781

This is one of Akamai's .. nice one... [#permalink] New post 10 Oct 2004, 00:15
This is one of Akamai's .. nice one...

http://www.manhattangmat.com

Praetorian
Kaplan Promo CodeKnewton GMAT Discount CodesManhattan GMAT Discount Codes
Manager
Manager
avatar
Joined: 28 Aug 2004
Posts: 205
Followers: 1

Kudos [?]: 1 [0], given: 0

GMAT Tests User
 [#permalink] New post 10 Oct 2004, 05:07
7/5.

Draw a radius from B to BZ (to from diameter YZ).

r = 360/pi (from the length-of-an-arc formula).

Draw a radius from B to A, results in a 'small' semicircle with diameter of 360/pi. Area of this 'small' circle is 90(180)/pi. You have to add it to the area of the sector YBC in the denominator of the ratio, and subtract it from the area of the semicircle in the numerator (together with the area of sector ABZ).

Now, angle YXA = 105, draw a line from X to Z, forming angle YXZ inscribed in a semicircle, = 90 degrees. Then angle AXZ is 105-90=15, and results in arc AZ of 30, with angle ABZ = 30 degrees.

From there, get the area of sector ABZ = 30/360pir^2 = (3*360)/pi

For the ratio, in the numerator, you have Area of semicircle - area of ABZ - area of 'small' semicircle

in the denominator, you have area of ABZ + area of small 'semicircle'

solve it out, and you should get 180*210/180*150 = 210/150=7/5.

After this one, I guess I will retire for today!
[/b]
Director
Director
User avatar
Joined: 31 Aug 2004
Posts: 609
Followers: 3

Kudos [?]: 21 [0], given: 0

GMAT Tests User
 [#permalink] New post 10 Oct 2004, 07:08
Praet,

Could you please repost it I guess there is a pb ...
CEO
CEO
avatar
Joined: 15 Aug 2003
Posts: 3470
Followers: 60

Kudos [?]: 665 [0], given: 781

 [#permalink] New post 10 Oct 2004, 07:26
twixt wrote:
Praet,

Could you please repost it I guess there is a pb ...


repost? ok, this might work...

http://www.manhattangmat.com/index.cfm?cid=11&sethome=1

Praetorian
Director
Director
User avatar
Joined: 31 Aug 2004
Posts: 609
Followers: 3

Kudos [?]: 21 [0], given: 0

GMAT Tests User
 [#permalink] New post 10 Oct 2004, 12:30
Thanks Praet,

Same method, same pain...

Answer is 7/5 after some nice plays with isoceles

Took me 9 mn...
Joined: 31 Dec 1969
Location: United States
Concentration: Marketing, Other
GMAT 1: 710 Q49 V38
GMAT 2: 660 Q V
GPA: 3.64
WE: Accounting (Accounting)
Followers: 0

Kudos [?]: 60 [0], given: 76305

Re: Manhattan GMAT problem of the week [#permalink] New post 10 Oct 2004, 18:00
Knowing this theorem can help a lot:
The opposite angles of quadrilaterals in circles are equal to two right angles.

If you complete the quadrilateral YCAX, then according to above theorem, ang YXC + ang YCA = 180

so,ang yca = 180-105=75

Another theorem to remember:
Angle at the centre is double the angle at the circumference if the angles have the same circumference as base.

Based on the above thm, ang YBA is double of the ang YCA.
So, ang YBA = 150

So ang YBC=180-150=30

Area of arc ybc = 0.5*r^2*pi/6

since 30 deg = pi/6

Area below = 0.5*r^2*pi/6 + pi*r^2/8

Area above = 0.5*r^2*5*pi/6 - pi*r^2/8

so ration above/below=7/5






Praetorian wrote:
This is one of Akamai's .. nice one...

http://www.manhattangmat.com

Praetorian
Intern
Intern
avatar
Joined: 10 Oct 2004
Posts: 12
Followers: 0

Kudos [?]: 0 [0], given: 0

Manhattan GMAT problem of this week [#permalink] New post 11 Oct 2004, 20:28
EDITED: anish, Manhattan gmat sells the archives of these questions. We may not want to be in copyright trouble :) thats why we usually only post the link, not the problem.
CEO
CEO
avatar
Joined: 15 Aug 2003
Posts: 3470
Followers: 60

Kudos [?]: 665 [0], given: 781

 [#permalink] New post 11 Oct 2004, 23:19
yes, the answer is indeed 7/5. go to the website to see the legend akamai's explanation. thanks all :-)
  [#permalink] 11 Oct 2004, 23:19
    Similar topics Author Replies Last post
Similar
Topics:
2 nice ppt's on run-on sentences and sub-verb agreement kingb 0 02 Oct 2012, 07:18
3 Just scored a nice 40 in the Verbal Section! I had this one Impenetrable 8 06 Mar 2012, 19:48
Nice one. download it and post your explanation. I'll post Ravshonbek 4 29 Aug 2007, 11:53
One of the bewakoof 0 06 Aug 2007, 14:10
Nice ONe... cybera 3 15 Jul 2005, 20:26
Display posts from previous: Sort by

This is one of Akamai's .. nice one...

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.