Sorry about that.
I think this one is a fairly simple one, but i feel like there must be an easy rule to remember as problems get increasingly difficult...
If y = 4 + (x - 3)^2, then y is lowest when x =
a - 14
b - 13
c - 0
d - 3
e - 4
the rule is to spread the condensed expression into the form of a quadratic expression IN CASE it's originally in condensed form
For example: y=ax^2+bx+c . This is a parabola. The biggest/ smallest of y then is the peak/ nadir of the parabola. The formula for this point is :
-( b^2-4ac)/ (-4a)
( if i remember correctly, i'll double-check it)
1) if the expression contains -x^2, the question asks for the peak/ the biggest value.
2) if the expression contains x^2, the question asks for the nadir/ the smallest value.
For example: y=x^2 - 6x + 12
the nadir is -[((-6)^2- 4*12*1)/ 4*1] = 3 --> the smallest value of y is 3
OR you can solve it another way by trying to group the expression into froms of -
(ax+b)^2 +c OR (ax+b)^2 +c
For example: x^2-6x+12= (x-3)^2+3