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This might have been posted before.. [#permalink] New post 10 Aug 2006, 15:00
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 [#permalink] New post 10 Aug 2006, 15:23
In other words, if y<x-10, is y<0 ?

(1) If x=8, we get y<-2 SUFF
(2) y=-20 SUFF

D
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 [#permalink] New post 10 Aug 2006, 15:34
I wud say D

x-y>10; is x-y>x+y

st1. x=8

lets see if x=8, then y has to be negative and smaller than <-2

pick y=-3; 8+3=11 which is > 10...

8-3=5, which is less than x+y...suff

st2. y=-20

which means x-y>10

means x-y >10, which implies x cud be 25 - -20 = 45 is greater than 10...
however x+y 25-20=5...

x cannot be negative and smaller than y...sufficient
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 [#permalink] New post 11 Aug 2006, 00:21
D

1) x = 8 hence y is negative.

hence x-y will always be positive but x+y will be less than 11
Suff

2) y = -20
Substitute values. Same as above.
  [#permalink] 11 Aug 2006, 00:21
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