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This one flummoxed me A, B, C, D, E, F, G, and H are

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This one flummoxed me A, B, C, D, E, F, G, and H are [#permalink] New post 15 Nov 2006, 06:27
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This one flummoxed me :?

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?
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 [#permalink] New post 15 Nov 2006, 06:47
Distance betwen G and H is = 5^13 -5^12 =4*5^12
Distance between each pt is constant.
Value of A = 5^13 - 7*4*5^12 = -23 *5^12
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 [#permalink] New post 15 Nov 2006, 07:10
Can you explain how you came up with that? I am having a hard time figuring it out. Thanks
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 [#permalink] New post 15 Nov 2006, 07:52
Let x be distance between 2 pts.
We have 8 pts from A to H

Value of A = Value of H -7x ( since numbers arranged as per their value on the number line)

Value of g and h are known so we can find out x.
x = value of H - value of G =5^13 -5^12 = 4*5^12
Value of A = 5^13 -7*4*5^12 = 5^12 (5 -28) = -23 *5^12
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 [#permalink] New post 15 Nov 2006, 11:36
Good one!...Tricked me! :wall
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 [#permalink] New post 15 Nov 2006, 12:09
I do not understand:


x = value of H - value of G =5^13 -5^12 =

How do you get this ->4*5^12



Value of A = 5^13 -7*4*5^12 = 5^12 (5 -28) = -23 *5^12
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 [#permalink] New post 15 Nov 2006, 12:32
typicalgmatter
distance between 2 points = 5^13 - 5^12 = (5^12)*5 - 5^12 = 5^12 (5-1) = 4*5^12.

Since there are 7 distance like that between A and H.
Value of A = 5^13 - 7*4*5^12 = 5^13 - 28*5^12 = 5^12 (5 - 28) = 5^12 * (-23)
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 [#permalink] New post 16 Nov 2006, 06:31
I'm still somewhat lost. Is A a negative number?
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 [#permalink] New post 16 Nov 2006, 14:32
This confused me initially because I in the stem it says the numbers are arranged according to SIZE, not value and so thought A could not be a negative number.
  [#permalink] 16 Nov 2006, 14:32
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This one flummoxed me A, B, C, D, E, F, G, and H are

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