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this one is yet more tricky and yet more freaky. Find all

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SVP
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Joined: 03 Feb 2003
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this one is yet more tricky and yet more freaky. Find all [#permalink] New post 18 Jun 2003, 23:10
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this one is yet more tricky and yet more freaky.
Find all its solutions.

(|2*Z|)!–|Z|=Z
SVP
SVP
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Joined: 03 Feb 2003
Posts: 1614
Followers: 5

Kudos [?]: 39 [0], given: 0

 [#permalink] New post 19 Jun 2003, 21:41
now it is correct.
it is imperative that you sovle the question, not simply guess it.

Post your solution here, please.
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PS: FACTORIAL2 [#permalink] New post 26 Jun 2003, 05:45
The LHS equation always gives positive values. Therefore, solution cannot lie in Z<0

Now for Z>=0, the equation can be rewritten as

(2Z)!-Z=Z

which gives (2Z-1)!=1 which is only possible for
(2Z-1) = 0 or 1. This leads to values of Z as 1 or 1/2
PS: FACTORIAL2   [#permalink] 26 Jun 2003, 05:45
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