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This problem is ridiculously simple, unless I'm missing

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This problem is ridiculously simple, unless I'm missing [#permalink] New post 22 May 2008, 22:35
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This problem is ridiculously simple, unless I'm missing something huge. Please show steps if you answer.

mv < pv < 0, is V > 0?

1. M < P
2. M < 0

I understand how you get at least B. But how is A sufficient -- how is it adding any data?
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Re: GMATPrep - Wow. [#permalink] New post 22 May 2008, 22:58
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dominion wrote:
This problem is ridiculously simple, unless I'm missing something huge. Please show steps if you answer.

mv < pv < 0, is V > 0?

1. M < P
2. M < 0

I understand how you get at least B. But how is A sufficient -- how is it adding any data?


D

statement 1 is suff, substitute in numbers
say M = 1, P = 2, V = -1, this cannot satisfy mv < pv < 0
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Re: GMATPrep - Wow. [#permalink] New post 22 May 2008, 23:07
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Consider inequality m<p and mv<pv

if we multiply p and m by positive v, we never change the order of p and m at the number line (v works as scale) and mv<mp is true.
For examle,
2<5 (v=2) 4<10
-2<5 (v=2) -4<10
-5<-2 (v=2) -10<-4

if we multiply p and m by negative v, we always change the order of p and m at the number line and mv<mp is false.

For examle,
2<5 (v=-2) -4>-10
-2<5 (v=-2) 4>-10
-5<-2 (v=-2) 10>4

That is why A also works.

P.S. I remember the question that seems to come from Prep2 but contains other symbols.
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Re: GMATPrep - Wow. [#permalink] New post 23 May 2008, 06:13
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dominion wrote:
This problem is ridiculously simple, unless I'm missing something huge. Please show steps if you answer.

mv < pv < 0, is V > 0?

1. M < P
2. M < 0

I understand how you get at least B. But how is A sufficient -- how is it adding any data?


This is a problem where you need to test numbers, which takes time and practice to get good at. I still mess it up so its not always perfect.

You could also realize that for S1: if M and V are + then that means V must be negative. But this won't work b/c the inequality would be untrue then. Take 2<3. (M<P) and V=-1

-2<-3???? this cannot be.
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Re: GMATPrep - Wow. [#permalink] New post 23 May 2008, 07:36
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dominion wrote:
This problem is ridiculously simple, unless I'm missing something huge. Please show steps if you answer.

mv < pv < 0, is V > 0?

1. M < P
2. M < 0

I understand how you get at least B. But how is A sufficient -- how is it adding any data?

Ans is A for me!
Because with stmt 2, let's have for {m,p,v} examples : {-1,1,2} and {-1,-3,-2}.
In the first case, v > 0 and v < 0 in second case!!
So stmt 2 is not sufficient!
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Re: GMATPrep - Wow. [#permalink] New post 23 May 2008, 08:07
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dominion wrote:
This problem is ridiculously simple, unless I'm missing something huge. Please show steps if you answer.

mv < pv < 0, is V > 0?

1. M < P
2. M < 0

I understand how you get at least B. But how is A sufficient -- how is it adding any data?


what is M and P are negative..

1) -3<-2
v=1..

M=2 and P=3
cannot be possible since v will have to be negative and -2<-3 is not possible

D it is..
Re: GMATPrep - Wow.   [#permalink] 23 May 2008, 08:07
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