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# This problem shows a diagram but can be just as easily

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Manager
Joined: 18 Jan 2007
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This problem shows a diagram but can be just as easily [#permalink]  08 Oct 2007, 17:03
(This problem shows a diagram but can be just as easily understood without one).

Two triangles exist each with the respective angles of x, y, and z. Triangle one has a base of 's', while triangle 2 has a base of 'S'. The triangle with base 'S' has twice the area of triangle 1. In terms of 's' what is 'S'?
Manager
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juaz [#permalink]  08 Oct 2007, 17:34
thats correct, but i knew that was the answer obviously. can you provide explanation/
Current Student
Joined: 31 Aug 2007
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1
KUDOS
1/2SH=2*1/2sh
SH=2sh

s/h=S/H
Sh=sH
H=Sh/s

S*S*h/s=2sh
S^2=2s^2
S=sqrt(2) * s

does anyone know a quicker way of solving this??
Director
Joined: 18 Jul 2006
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Re: juaz [#permalink]  08 Oct 2007, 18:05
dr908 wrote:
thats correct, but i knew that was the answer obviously. can you provide explanation/

Area is proportional to side*side if angles are same.
e.g. area of a triangle = 1/2*s^2*(sin x)

If angles are same, equation can be written as A = k * s^2
A1 = 2A2
=> S^2 = 2*s^2
=> S = sqrt2 * s

HTH
Director
Joined: 17 Sep 2005
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young_gun wrote:
1/2SH=2*1/2sh
SH=2sh

s/h=S/H
Sh=sH
H=Sh/s

S*S*h/s=2sh
S^2=2s^2
S=sqrt(2) * s

does anyone know a quicker way of solving this??

Correct.

Both Triangles are "Similar Triangles".
So the ratio of the height to the base of both triangles will be same.

- Brajesh
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