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This should be fairly easy If x<=4 and y>=12 what is

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This should be fairly easy If x<=4 and y>=12 what is [#permalink]

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08 Feb 2004, 14:38
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This should be fairly easy
If x<=4 and y>=12 what is the range of set { 5,8,x,y }

1) 3x+ 5y = 72
2) -7x+7y = 56
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08 Feb 2004, 15:00
is it C as for statement (1) i am getting x=4 and y=12 and x= -6 and y=18 and for statement (2) x= 4 and y= 12. So by combining both we get x=4 and y=12.
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08 Feb 2004, 23:45
I think the answer is B. I solved this problem via the graphical analysis which shows that Statement I gives a host of values of (x,y) satisfying the given conditions and hence the answer is not unique.
Statement II gives only one value of (x,y)=(4,12) which satisfies all the conditions ie. x <=4,y>=12 and -7x+7y=56. Hence the range of the given set of nos. is unique ie. (12-4)=8.

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09 Feb 2004, 01:39
Answer would be E if the question is not modified to assume that x and y are integers.
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09 Feb 2004, 09:42
anupag wrote:
Answer would be E if the question is not modified to assume that x and y are integers.

I think I agree with amips2000. We do not have to have the clarification regarding whether X and Y are integer or not. B is sufficient.
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09 Feb 2004, 09:53
Hi rakesh,

I got you again.
Didn't I warn you in my previous post.

The answer is indeed B. This got me as well.

x <=4 means x is the smallest possible number in the given set
y >=12 means y is the largest possible number in the given set.
Range = Y-X. Infinite numbe of combinations possible.

B gives you this difference and hence the sufficient condition.
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09 Feb 2004, 23:47
Thanks Anand! Now I know that B is indeed the answer. Nothing wrong with C but when we can get the unique answer by B then its stupid to opt for C.
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