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# Three bells chime at intervals of 18 min., 24 min. and 32 mi

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Three bells chime at intervals of 18 min., 24 min. and 32 mi [#permalink]  25 Oct 2010, 01:17
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Three bells chime at intervals of 18 min., 24 min. and 32 min. respectively. At a certain time they begin together. What length of time will elapse before they chime together again?

A. 2 hr. and 24 min.
B. 4 hr. and 48 min.
C. 1 hr. and 36 min.
D. 5 hr.
E. 2 hr.
[Reveal] Spoiler: OA
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Re: Three bells chime at intervals of 18 min., 24 min. and 32 mi [#permalink]  25 Oct 2010, 02:06
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feruz77 wrote:
Three bells chime at intervals of 18 min., 24 min. and 32 min. respectively. At a certain time they begin together. What length of time will elapse before they chime together again?
a) 2 hr. and 24 min.
b) 4 hr. and 48 min.
c) 1 hr. and 36 min.
d) 5 hr.
e) 2 hr.

It should be simple. All the three bells will chime again together whenver their time intervals intersect eachother.
So the LCM of the three time intervals (18, 24,32) would be the answer.
LCM (18, 24, 32) = 288 => 4 hours 48 mins.
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Re: Three bells chime at intervals of 18 min., 24 min. and 32 mi [#permalink]  25 Oct 2010, 08:55
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Agree 4 hours 48 mins solved it the same exact way
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Re: Three bells chime at intervals of 18 min., 24 min. and 32 mi [#permalink]  12 Aug 2014, 05:45
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Re: Three bells chime at intervals of 18 min., 24 min. and 32 mi [#permalink]  12 Aug 2014, 23:02
LCM of 18, 24, 32

$$= 2^6 * 3^2 = 288$$

$$\frac{288}{60} = 4$$ Hrs something

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Three bells chime at intervals of 18 min., 24 min. and 32 mi [#permalink]  08 Nov 2014, 01:01
PareshGmat wrote:
LCM of 18, 24, 32

$$= 2^6 * 3^2 = 288$$

$$\frac{288}{60} = 4$$ Hrs something

This is wrong! It should be 2to the power of 5 and not 6
Three bells chime at intervals of 18 min., 24 min. and 32 mi   [#permalink] 08 Nov 2014, 01:01
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# Three bells chime at intervals of 18 min., 24 min. and 32 mi

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