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Three boxes of supplies have an average weight of 7 kgs and

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Three boxes of supplies have an average weight of 7 kgs and [#permalink] New post 28 Sep 2007, 10:18
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Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

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VP
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Re: PS question [#permalink] New post 28 Sep 2007, 10:28
varunk wrote:
Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

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2. 2
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good one

x, 9, y --> in ascending order thus 9 is median
y is equal or greater than 9

x+9+y=21
x+y=12
in order for the lightest X to be max weigh heaviest Y should be 9 thus the lightest weighs then 3
C

Last edited by Ravshonbek on 28 Sep 2007, 10:30, edited 1 time in total.
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Re: PS question [#permalink] New post 28 Sep 2007, 10:35
varunk wrote:
Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1
2. 2
3. 3
4. 4
5. 5


It's 3.

Avg: [A + B + C]/3 = 21
Median = 9 ==> B = 9 ==> A + C = 12

Max value of A can be : 3
and the boxes are : 3, 9, 9
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 [#permalink] New post 28 Sep 2007, 10:43
Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?
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 [#permalink] New post 28 Sep 2007, 10:45
varunk wrote:
Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?


yep it should be 10 but if we assume it is 10 then we end up with 2,9,10 but the only max it can get is 3 and 3,9,9 and the order is still in ascending form
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Re: PS question [#permalink] New post 28 Sep 2007, 11:30
varunk wrote:
Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1
2. 2
3. 3
4. 4
5. 5


For lightest to have maximum weight , the third one should have the same weight as the middle one ( 9 )
that gives x + 9 + 9 = 3 * 7 => 3 answer
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 [#permalink] New post 28 Sep 2007, 14:33
Ravshonbek wrote:
varunk wrote:
Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?


yep it should be 10 but if we assume it is 10 then we end up with 2,9,10 but the only max it can get is 3 and 3,9,9 and the order is still in ascending form


Yes, this is the logic behind....

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Re: PS question [#permalink] New post 28 Sep 2007, 18:10
varunk wrote:
Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1
2. 2
3. 3
4. 4
5. 5



S/N=A

7=S/3 ---> S = 21.

So max weight will be 21-9+9 = 3.

I had this on my prep, i got answer but didn't realize i had clicked the wrong answer =(
Re: PS question   [#permalink] 28 Sep 2007, 18:10
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