Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Three boxes of supplies have an average weight of 7 kgs and [#permalink]
28 Sep 2007, 10:18

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

100% (00:00) correct
0% (00:00) wrong based on 6 sessions

Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1 2. 2 3. 3 4. 4 5. 5

good one

x, 9, y --> in ascending order thus 9 is median
y is equal or greater than 9

x+9+y=21
x+y=12
in order for the lightest X to be max weigh heaviest Y should be 9 thus the lightest weighs then 3
C

Last edited by Ravshonbek on 28 Sep 2007, 10:30, edited 1 time in total.

Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1 2. 2 3. 3 4. 4 5. 5

It's 3.

Avg: [A + B + C]/3 = 21
Median = 9 ==> B = 9 ==> A + C = 12

Max value of A can be : 3
and the boxes are : 3, 9, 9

Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?

yep it should be 10 but if we assume it is 10 then we end up with 2,9,10 but the only max it can get is 3 and 3,9,9 and the order is still in ascending form

Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1 2. 2 3. 3 4. 4 5. 5

For lightest to have maximum weight , the third one should have the same weight as the middle one ( 9 )
that gives x + 9 + 9 = 3 * 7 => 3 answer

Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?

yep it should be 10 but if we assume it is 10 then we end up with 2,9,10 but the only max it can get is 3 and 3,9,9 and the order is still in ascending form

Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?

1. 1 2. 2 3. 3 4. 4 5. 5

S/N=A

7=S/3 ---> S = 21.

So max weight will be 21-9+9 = 3.

I had this on my prep, i got answer but didn't realize i had clicked the wrong answer =(