|
Author |
Message |
|
TAGS:
|
|
|
Intern
Joined: 05 Sep 2007
Posts: 42
Followers: 0
Kudos [?]:
16
[0], given: 0
|
Three boxes of supplies have an average weight of 7 kgs and [#permalink]
 28 Sep 2007, 11:18
Question Stats:
0% (00:00) correct
 0% (00:00) wrong based on 0 sessions
Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?
1. 1
2. 2
3. 3
4. 4
5. 5
|
|
|
|
|
|
|
VP
Joined: 09 Jul 2007
Posts: 1114
Location: London
Followers: 4
Kudos [?]:
55
[0], given: 0
|
varunk wrote: Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?
1. 1
2. 2
3. 3
4. 4
5. 5
good one
x, 9, y --> in ascending order thus 9 is median
y is equal or greater than 9
x+9+y=21
x+y=12
in order for the lightest X to be max weigh heaviest Y should be 9 thus the lightest weighs then 3
C
Last edited by Ravshonbek on 28 Sep 2007, 11:30, edited 1 time in total.
|
|
|
|
|
|
Intern
Joined: 15 Mar 2007
Posts: 48
Followers: 0
Kudos [?]:
0
[0], given: 0
|
varunk wrote: Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?
1. 1
2. 2
3. 3
4. 4
5. 5
It's 3.
Avg: [A + B + C]/3 = 21
Median = 9 ==> B = 9 ==> A + C = 12
Max value of A can be : 3
and the boxes are : 3, 9, 9
|
|
|
|
|
|
Intern
Joined: 05 Sep 2007
Posts: 42
Followers: 0
Kudos [?]:
16
[0], given: 0
|
Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?
|
|
|
|
|
|
VP
Joined: 09 Jul 2007
Posts: 1114
Location: London
Followers: 4
Kudos [?]:
55
[0], given: 0
|
varunk wrote: Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...?
yep it should be 10 but if we assume it is 10 then we end up with 2,9,10 but the only max it can get is 3 and 3,9,9 and the order is still in ascending form
|
|
|
|
|
|
Director
Joined: 08 Jun 2007
Posts: 586
Followers: 1
Kudos [?]:
66
[0], given: 0
|
varunk wrote: Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?
1. 1
2. 2
3. 3
4. 4
5. 5
For lightest to have maximum weight , the third one should have the same weight as the middle one ( 9 )
that gives x + 9 + 9 = 3 * 7 => 3 answer
|
|
|
|
|
|
Director
Joined: 17 Sep 2005
Posts: 934
Followers: 1
Kudos [?]:
14
[0], given: 0
|
Ravshonbek wrote: varunk wrote: Thanks folks, but I am confused...why is the the third number in ascending order is equal to 9...shouldn't it be 10 i.e. one more than the median...? yep it should be 10 but if we assume it is 10 then we end up with 2,9,10 but the only max it can get is 3 and 3,9,9 and the order is still in ascending form Yes, this is the logic behind....
-Brajesh
|
|
|
|
|
|
CEO
Joined: 29 Mar 2007
Posts: 2618
Followers: 13
Kudos [?]:
142
[0], given: 0
|
varunk wrote: Three boxes of supplies have an average weight of 7 kgs and a median weight of 9 Kgs. What is the maximum possible weight, in kilograms, of the lightest box?
1. 1
2. 2
3. 3
4. 4
5. 5
S/N=A
7=S/3 ---> S = 21.
So max weight will be 21-9+9 = 3.
I had this on my prep, i got answer but didn't realize i had clicked the wrong answer =(
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
close
