It is 39/52 * 38/51 * 37/50 = Ans d:
None of the cards has to be heart. => all the three can be hearts or any one can be heart or any two can be hearts. You need to add up all these before you subtract from 1. That is where the second answer you have given is different.
1. Three cards are drawn from an ordinary 52-card deck without
replacement (drawn cards are not placed back in the deck). The probability that none of the three cards is a heart is as follows
my problem below=>
ok it is a simple problem, but my question concerns the two ways of finding the solution.
1. Prob (first card is not heart ) * Prob (second card is not heart GIVEN THAT first is not heart) * Prob (Third card is not heart GIVEN THAT first two are not hearts) = required Prob
2. Prob (first card is heart ) * Prob (second card is heart GIVEN THAT first is heart) * Prob (Third card is heart GIVEN THAT first two are hearts) = Prob => 1-Prob = required Prob
can someon explain to me why i get two different solutions ???
Thnx & Rgds,