bschool83 wrote:

Three children, Alice, Brian, and Chris have a total of $1.20 between them. Does Chris have the most money?

(1) Alice has 35 cents.

(2) Chris has 40 cents.

\(A + B + C = 120\), is \(C > A\) and \(C>B\)?

1) \(A = 35\), therefore \(B + C = 120 - 35 = 85\).

It could be that \(C = 84\) and \(A = 1\), or that \(C = 1\) and \(B = 84\). \(C\) is greater than both \(A\) and \(B\) in one scenario, but not in the other. Insufficient.

2) \(C = 40\), therefore \(A + B = 120 - 40 = 80\).

This means that the average of \(A\) and \(B\) is \(40\), and either \(A = B = 40\), or \(A > 40 > B\), or \(B > 40 > A\).

Either way, \(C\) is NOT greater than both \(A\) and \(B\).

Sufficient.