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Three children, Alice, Brian, and Chris have a total of

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Three children, Alice, Brian, and Chris have a total of [#permalink] New post 24 Jul 2011, 14:30
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Three children, Alice, Brian, and Chris have a total of $1.20 between them. Does Chris have the most money?

(1) Alice has 35 cents.

(2) Chris has 40 cents.
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Re: DS - 700 level - money [#permalink] New post 24 Jul 2011, 19:01
bschool83 wrote:
Three children, Alice, Brian, and Chris have a total of $1.20 between them. Does Chris have the most money?

(1) Alice has 35 cents.

(2) Chris has 40 cents.


A + B + C = 120, is C > A and C>B?

1) A = 35, therefore B + C = 120 - 35 = 85.

It could be that C = 84 and A = 1, or that C = 1 and B = 84. C is greater than both A and B in one scenario, but not in the other. Insufficient.

2) C = 40, therefore A + B = 120 - 40 = 80.

This means that the average of A and B is 40, and either A = B = 40, or A > 40 > B, or B > 40 > A.

Either way, C is NOT greater than both A and B.

Sufficient.

[Reveal] Spoiler:
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Re: Three children, Alice, Brian, and Chris have a total of [#permalink] New post 27 Mar 2012, 21:11
I have to disagree. In the case where each have 40c ie you have a set (40, 40, 40) they each individually have the most (ie the highest value = 40) and it so happens they each individually have the least, again 40.

Since this provides two cases, Brian having the most when they all share the most (similar to tied for 1st place - they are equally best) and Brian not having the most when any other values are chosen, one requires both (1) and (2) to determine if Chris does/doesn't have the most.

Clearly this is a definition debate around "most" and ties for most, and the question would likely (hopefully) be thrown out by the gmac folks!
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Re: Three children, Alice, Brian, and Chris have a total of [#permalink] New post 27 Mar 2012, 23:59
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bschool83 wrote:
Three children, Alice, Brian, and Chris have a total of $1.20 between them. Does Chris have the most money?

(1) Alice has 35 cents.

(2) Chris has 40 cents.


This is a poor quality question because of its ambiguous wording.

For statement (2) if all 3 children have 40 cents, does that mean that all of them have the most money or none of them have the most money? How are we supposed to treat ties?

So, I'd advice not to study this question at all.
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Re: Three children, Alice, Brian, and Chris have a total of [#permalink] New post 29 Mar 2012, 02:58
Answer should be C, what is the OA?

The explanation is in either of the case A or B, Chris may or may not have the most money.
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Re: Three children, Alice, Brian, and Chris have a total of [#permalink] New post 29 Mar 2012, 04:16
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monu1101 wrote:
Answer should be C, what is the OA?

The explanation is in either of the case A or B, Chris may or may not have the most money.


Welcome to GMAt Club.

Please check this: three-children-alice-brian-and-chris-have-a-total-of-117635.html#p1066131 So as you can see it's a poorly designed question, and one can justify B as well as C for it, and that's exactly why this kind of question has zero chances of appearing on the real test.

By the way the OA for this question is B, though it's completely irrelevant since as discussed the question is quite ambiguous.

Hope it helps.
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: Three children, Alice, Brian, and Chris have a total of   [#permalink] 29 Mar 2012, 04:16
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