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Three different locations are represented on a map by the [#permalink] New post 22 Jul 2009, 02:57
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Three different locations are represented on a map by the points X,Y and Z. What is the actual distance between the locations represented on the map by X and Y ?
( 1cm = 200 KM)

1. Z is to the left of X and Y is to the right of X.
2. X is 4 cms from Z, and Y is 3 cms from Z.


Please explain.

Thanks
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Re: DS Q [#permalink] New post 22 Jul 2009, 03:25
E none.
We do not know whether they lie on a line or not. So we can not say anything.
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Re: DS Q [#permalink] New post 22 Jul 2009, 03:39
maliyeci wrote:
E none.
We do not know whether they lie on a line or not. So we can not say anything.


Well I agree but if we use both the statements then we will get shape which is shown in the figure, in that case cant we calculate the distance ?
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Re: DS Q [#permalink] New post 22 Jul 2009, 03:49
Can't they be on the same line? 3-4-5 triangle is a very special case. You are doing wrong I think.
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Re: DS Q [#permalink] New post 22 Jul 2009, 04:15
maliyeci wrote:
Can't they be on the same line? 3-4-5 triangle is a very special case. You are doing wrong I think.


I agree this is might be a special case and this is exactly what I am want to know where am I going wrong.

Anyway the points can’t be on the same line because as per the 1st statement Z is to left of X and Y is to right of X and from the 2nd statement the distance between Z and Y is 3 which is not possible because in that X goes to the right of Y.

Cheers
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Re: DS Q [#permalink] New post 22 Jul 2009, 04:21
Yes you are right. They can not be on the same line.
But there are unlimited number of triangles with 2 sides are 3 and 4.
It may vary from 3-4-1,000001 to 3-4-6,999999999.
Left of x and right of x may limit to some values. But it does not limit to 3-4-5
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Re: DS Q [#permalink] New post 22 Jul 2009, 04:24
Good question.
I think answer should be C.

Because when we combine 1 and 2, it is implicit that points are not on the same line.
For.eg. following figure is not possible.
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Re: DS Q [#permalink] New post 22 Jul 2009, 04:39
I can not find the distance with 2 statements. Somebody can show me the calculations?
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Re: DS Q [#permalink] New post 22 Jul 2009, 04:54
Hmm...even I am wondering now :)
We are not given the angle...we only know lengths of two sides....so length of third side can be anything...

OA Pls!
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Re: DS Q [#permalink] New post 22 Jul 2009, 05:23
maliyeci wrote:
I can not find the distance with 2 statements. Somebody can show me the calculations?


Yes maliyeci you are right, the 3rd side can be 2 or may be 6 ... my bad I assumed that it will be 5 ( general notion while doing questions related to triangles :) )

Anyway thanks for making me understand ..the new lesson for the day .. i.e STOP Assuming :D

Cheers !
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Re: DS Q [#permalink] New post 22 Jul 2009, 05:26
Economist wrote:
Hmm...even I am wondering now :)
We are not given the angle...we only know lengths of two sides....so length of third side can be anything...

OA Pls!



Yes, the OA is E, infact I just assumed the 3rd side to be 5 .. my bad :(

Anyway Thanks..

Cheers !
Re: DS Q   [#permalink] 22 Jul 2009, 05:26
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