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Three groups of children contain (i) 3 girls and 1 boy; (ii)

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Three groups of children contain (i) 3 girls and 1 boy; (ii) [#permalink] New post 10 Dec 2003, 06:17
Three groups of children contain (i) 3 girls and 1 boy; (ii) 3 girls and 3 boys; (iii) 2 boys and 1 girl. One child is selected at random from each group. Find the probability that the three selected children comprise of 1 girl and 2 boys.
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 [#permalink] New post 10 Dec 2003, 06:35
possible outcomes bbb,ggg,bgg,bbg, the prob of having bgg is 1/4
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 [#permalink] New post 10 Dec 2003, 06:47
such q-s will never appear on the real test.
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 [#permalink] New post 10 Dec 2003, 06:51
Then what kinda questions can we expect on the real test??

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 [#permalink] New post 10 Dec 2003, 07:30
basic probability, no more
this question requires applying a full probability formula.
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 [#permalink] New post 10 Dec 2003, 08:13
stolyar wrote: such q-s will never appear on the real test.

It's not a terribly difficult question, however.

GROUP 1: P OF GIRL .75
GROUP 2: P OF GIRL .50
GROUP 3: P OF GIRL .33 (APPX)

GBB: .75*.5*.67 .25125
BGB: .25*.5*.67 .08375
BBG: .25*.5*.33 .04125
---------
.37625
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 [#permalink] New post 12 Dec 2003, 20:00
stolyar wrote:
basic probability, no more
this question requires applying a full probability formula.


agreed..
BBG=1/4.3/6.1/3
BGB=1/4.3/6.2/3
GBB=3/4.3/6.2/3

prob. = 3/8
  [#permalink] 12 Dec 2003, 20:00
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