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# Three groups of children contain (i) 3 girls and 1 boy; (ii)

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Intern
Joined: 29 Aug 2003
Posts: 29
Location: Mumbai
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Kudos [?]: 0 [0], given: 0

Three groups of children contain (i) 3 girls and 1 boy; (ii) [#permalink]  10 Dec 2003, 05:17
Three groups of children contain (i) 3 girls and 1 boy; (ii) 3 girls and 3 boys; (iii) 2 boys and 1 girl. One child is selected at random from each group. Find the probability that the three selected children comprise of 1 girl and 2 boys.
Director
Joined: 13 Nov 2003
Posts: 790
Location: BULGARIA
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Kudos [?]: 30 [0], given: 0

possible outcomes bbb,ggg,bgg,bbg, the prob of having bgg is 1/4
SVP
Joined: 03 Feb 2003
Posts: 1607
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Kudos [?]: 84 [0], given: 0

such q-s will never appear on the real test.
Intern
Joined: 29 Aug 2003
Posts: 29
Location: Mumbai
Followers: 0

Kudos [?]: 0 [0], given: 0

Then what kinda questions can we expect on the real test??

Gaurav.
SVP
Joined: 03 Feb 2003
Posts: 1607
Followers: 7

Kudos [?]: 84 [0], given: 0

basic probability, no more
this question requires applying a full probability formula.
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
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Kudos [?]: 11 [0], given: 0

stolyar wrote: such q-s will never appear on the real test.

It's not a terribly difficult question, however.

GROUP 1: P OF GIRL .75
GROUP 2: P OF GIRL .50
GROUP 3: P OF GIRL .33 (APPX)

GBB: .75*.5*.67 .25125
BGB: .25*.5*.67 .08375
BBG: .25*.5*.33 .04125
---------
.37625
Director
Joined: 13 Nov 2003
Posts: 971
Location: Florida
Followers: 1

Kudos [?]: 35 [0], given: 0

stolyar wrote:
basic probability, no more
this question requires applying a full probability formula.

agreed..
BBG=1/4.3/6.1/3
BGB=1/4.3/6.2/3
GBB=3/4.3/6.2/3

prob. = 3/8
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