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# Three of the six vertices of a regular hexagon are chosen at

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Intern
Joined: 12 Dec 2004
Posts: 33
Followers: 0

Kudos [?]: 0 [0], given: 0

Three of the six vertices of a regular hexagon are chosen at [#permalink]  01 Jan 2005, 22:16
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Difficulty:

(N/A)

Question Stats:

100% (01:04) correct 0% (00:00) wrong based on 1 sessions
Three of the six vertices of a regular hexagon are chosen at
random. What is the probability that the triangle drawn with these
three vertices is equilateral.

a) 1/2
b) 1/5
c) 1/10
d) 1/20
e) 3/20
Director
Joined: 07 Nov 2004
Posts: 694
Followers: 4

Kudos [?]: 29 [0], given: 0

C?

Total number of ways of picking 3 vertices = 6C3= 20
Only two sets of 3 vertices will have an equilateral triangle.

So probability = 2/20 = 1/10
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