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Three of the six vertices of a regular hexagon are chosen at

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Intern
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Joined: 12 Dec 2004
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Three of the six vertices of a regular hexagon are chosen at [#permalink] New post 01 Jan 2005, 22:16
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A
B
C
D
E

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100% (01:04) correct 0% (00:00) wrong based on 1 sessions
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Three of the six vertices of a regular hexagon are chosen at
random. What is the probability that the triangle drawn with these
three vertices is equilateral.

a) 1/2
b) 1/5
c) 1/10
d) 1/20
e) 3/20
Director
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Joined: 07 Nov 2004
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 [#permalink] New post 02 Jan 2005, 06:17
C?

Total number of ways of picking 3 vertices = 6C3= 20
Only two sets of 3 vertices will have an equilateral triangle.

So probability = 2/20 = 1/10
  [#permalink] 02 Jan 2005, 06:17
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Three of the six vertices of a regular hexagon are chosen at

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