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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
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Bunuel wrote:
Three table runners have a combined area of 200 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner?[/b]

(A) 18 square inches
(B) 20 square inches
(C) 24 square inches
(D) 28 square inches
(E) 30 square inches

Kudos for a correct solution.


Solution : After overlapping, let the area that is covered by single layer of three table runners be x,y and z. Let area covered by first and second, second and third, and third and first be a,b and c respectively. Let the area covered by all three be d.
So, x+y+z+(a+b+c)+d = 0.8(175) = 140. We know that area that is covered by exactly two layers(a+b+c) = 24
x+y+z+d = 116.-->(1)

But, combined area = x+a+c+d+y+a+b+d+z+b+c+d = x+y+z+2(a+b+c)+3d = 200
x+y+z+3d = 152.-->(2)

From (1) and (2), 2d = 36 ==> d = 18.

Option A.
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
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Bunuel wrote:
Three table runners have a combined area of 200 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner?[/b]

(A) 18 square inches
(B) 20 square inches
(C) 24 square inches
(D) 28 square inches
(E) 30 square inches

Kudos for a correct solution.


Let x be the area that is covered by three layers of runners.
Total area covered by three runners is 200
Total area of table covered is 80% of 175 = 140
So, the overlapping area will be
A+B+C - AuBuC = 200-140 = 60

It is given that sum of exactly 2 overlapping areas is 24
Total overlapping area = sum of exactly 2 groups overlap + 2*(all three)
So,
2x+24 = 60
or 2x= 60- 24 = 36
or x=18

Answer:- A
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
Surplus -> Direct sum of three sets - union of three sets.
-> 200 - .75*175
-> 200 - 140 -> 60
Surplus -> Sum of three combinations of intersection of two sets + 2 * (Intersection of three sets)
i.e. 60 -> 24 + 2 * (Intersection of three sets)
so, Intersection of three sets -> 18
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
How come Neither is 0?.If total table area covered is 80% ,then no area covered is 20%,right.Not able to understand why Neither is 0 and total area is considered 140 instead of 175
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
bhamini1 wrote:
How come Neither is 0?.If total table area covered is 80% ,then no area covered is 20%,right.Not able to understand why Neither is 0 and total area is considered 140 instead of 175


neither here refers to the area of table covers that doesn't cover anything , not that area of the table that isn't covered
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
Bunuel wrote:
Three table runners have a combined area of 200 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner?

(A) 18 square inches
(B) 20 square inches
(C) 24 square inches
(D) 28 square inches
(E) 30 square inches

Kudos for a correct solution.



3 groups only?

Given: Three table runners have a combined area of 200 square inches. => n(A) + n(B) + n(C) = 200

Total = n(A) + n(B) + n(C) + None - (2 groups only) - 2(3 groups only)
.8 * 175 = 200 + 0 - 24 -2(3 groups only)
140 = 200 + 0 - 24 -2x => 2x = 60 - 24 => x = 36/2 = 18 => A
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
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I have spent too long on this question. And I'm sure dealing with this question was not too fun for people who for people who aren't the best at math.

I think the issue arises primarily because of the way the question is framed and also the mental images that came up in my head when I was reading this question.

Question:
Three table runners have a combined area of 200 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner?

Information we are provided:
1. there are 3 table runners.
2. area of the table = 175 sq inches
3. The total area of the table covered by the runners = 80% of the table area. i.e. 140 sq inches.
4. Combined area of the runners = 200 sq inches

overlapping section= 200 -140 = 60 (area that is covered by at least two layers)
We have the information that the area that is covered by exactly two layers = 24
total overlapping area = sum of exactly 2 groups overlap + 2*(all three)
area that is covered by exactly 3 layers = 60 - 24 = 36/2
area covered by exactly 3 layers = 18
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
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Re: Three table runners have a combined area of 200 square inches. By over [#permalink]
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