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Three units of A, B, C of a factory produce 25%, 25% and

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Three units of A, B, C of a factory produce 25%, 25% and [#permalink] New post 15 May 2004, 22:27
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Three units of A, B, C of a factory produce 25%, 25% and 50"% of its production respectively. If the percentages of defective items produced by the three units A, B, C are respectively 1%, 2% and 3% and an item selected at random is found to be defective, find the probability that it is produced by the unit (i) A; (ii) B
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 [#permalink] New post 16 May 2004, 04:00
A produces 25 items
B produces 25
C preoduces 50 items

No of deffective by A = 0.25
No of deffective by B = 0.5
No of deffective by C = 1.5

P(deffective is from A ) = 0.25 / ( 0.25+0.5+1.5 ) = 1/9
p(deffective is from B ) = 0.5 / ( 0.25+0.5+1.5) = 2/9
  [#permalink] 16 May 2004, 04:00
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Three units of A, B, C of a factory produce 25%, 25% and

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