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To everyone out there: this is good practice I got

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To everyone out there: this is good practice I got [#permalink] New post 01 Aug 2003, 15:29
00:00
A
B
C
D
E

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(N/A)

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100% (03:13) correct 0% (00:00) wrong based on 6 sessions
To everyone out there: this is good practice

I got the right answers but you have to be fast.

Which of the following could be the exact value of n^4, where n is an integer?

1) 1.6 * 10 ^23
2) 1.6 * 10 ^ 21
3) 1.6 * 10 ^ 22
4) 1.6 * 10 ^23
5) 1.6 * 10 ^24

If s(t^3)(u^4)>0, then which of the following is positive

1) ST
2) SU
3) TU
4) STU
5) st^2
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 [#permalink] New post 02 Aug 2003, 07:27
1. 1.6 * 10 ^ 21
= 16 * 10^20
= 2^4 * (10^5)^4
= (2*10^5)^4

2. Did not understand the question
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Hi [#permalink] New post 02 Aug 2003, 07:42
1) is not right. Even the 49ers club can slip up every now and then. Keep trying. :lol:

2) Which of the following is positive, sorry :cry:
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 [#permalink] New post 03 Aug 2003, 16:03
I didn't understand question 1. Can anyone tell me, what the
question is asking for?
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 [#permalink] New post 04 Aug 2003, 07:29
VT,

When I wrote (1), I meant the first part of the problem. If you see the expression, you will see that my choice was #2 (1.6 * 10 ^ 21).

KPadma,
It is asking for the expression which can be formatted in the form of n^4, where n is a integer. You will see why expression#2 (1.6 * 10 ^ 21) can be formatted into that form.
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 [#permalink] New post 04 Aug 2003, 07:40
I can't take the test for you. Think about it prakunda, get back to me on my circumference problem the overlapping arc.

( x ) ^ 4
It cannot be one.
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 [#permalink] New post 04 Aug 2003, 08:47
VT,

Soory I confused you. The correct choice for the first part of the problem is the number (2) choice which is : 1.6 * 10 ^ 21

Because,

1.6 * 10^21
= 16 * 10^20
= 2^4 * (10^5) ^4
= (2*10^5)^4
= (200000)^4

Which is in the format n^4 where n is an integer. Here your n will be 200000. Mark option B - it is correct.
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Hi [#permalink] New post 04 Aug 2003, 18:56
E is right for one, A for two.
ETS answer, no argument.
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 [#permalink] New post 04 Aug 2003, 19:25
VT,
If (e) is the right answer then 1.6 * 10 ^24 can be expressed as n^4. Which is wrong even if ETS says it. Because, if you take
1.6 * 10 ^24
= 16 * 10^23
= 2^4 * 10 ^ 20 * 10^3
= 2^4 * (10^5)^4 * 1000
= (2*10^5)^4 * 1000

which clearly is not in the form n^4. If (E) is the answer, please recheck the question. Thanks
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Hi [#permalink] New post 04 Aug 2003, 20:39
I swear on ETS's bible E is right.

:lol:
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 [#permalink] New post 04 Aug 2003, 23:19
stolyar wrote:
Q1 (2)
Q2 (1)


Stolyar,

In the second question, both ST as well as ST^2 are positive. Why did you choose ST ?
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 [#permalink] New post 05 Aug 2003, 00:23
ST^2 or (ST)^2

my rationale is to terminate even powers
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 [#permalink] New post 05 Aug 2003, 01:48
stolyar wrote:
ST^2 or (ST)^2

my rationale is to terminate even powers


I'm sorry I didn't get that. Could you elaborate please? :wall

Thanks!
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 [#permalink] New post 05 Aug 2003, 02:09
s(t^3)(u^4)>0

(t^2)(u^4) is nonnegative. Terminate it.

st>0
  [#permalink] 05 Aug 2003, 02:09
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