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To mail a package, the rate is x cents for the first pound [#permalink]
25 Aug 2011, 08:02
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15% (low)
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72% (02:03) correct
28% (00:56) wrong based on 107 sessions
To mail a package, the rate is x cents for the first pound and y cents for each additional pound, where x>y. Two packages weighing 3 pounds and 5 pounds, respectively can be mailed seperately or combined as one package. Which method is cheaper and how much money is saved?
A. Combined, with a saving of x-y cents B. Combined, with a saving of y-x cents C. Combined, with a saving of x cents D. Separately, with a saving of x-y cents E. Separately, with a saving of y cents
hi there.. could anyone pls help to explain what does it mean by ".......saving of x-y cents, y-x cents" pls?I have difficult understand it..
Re: To mail a package [#permalink]
25 Aug 2011, 08:13
To mail a package, the rate is x cents for the first pound and y cents for each additional pound, where x>y. This means it costs x cent for the first pound in weight for example, 20 cents for the first pound. It costs y cents for the every pound in weight above this, for example 10 cents for pound 2 and 10 cents for pound 3. x is more than y. for example 20 cents vs. 10 cents
Two packages weighing 3 pounds and 5 pounds, respectively can be mailed seperately or combined as one package. Which method is cheaper and how much money is saved?
Re: To mail a package [#permalink]
25 Aug 2011, 08:42
miweekend wrote:
nammers wrote:
To mail a package, the rate is x cents for the first pound and y cents for each additional pound, where x>y. This means it costs x cent for the first pound in weight for example, 20 cents for the first pound. It costs y cents for the every pound in weight above this, for example 10 cents for pound 2 and 10 cents for pound 3. x is more than y. for example 20 cents vs. 10 cents
Two packages weighing 3 pounds and 5 pounds, respectively can be mailed seperately or combined as one package. Which method is cheaper and how much money is saved?
Combined is cheaper as we maximise y and minimize x. Answer is: 1) Combined, with a saving of x-y cents
thank you nammer.
I saw you are using (Separate Cost) - (Combined Cost). So it is (2x+6y) - (x+7y) = 2x + 6y - x - 7y = x-y <--- it makes sense here to conclude answer is A.
However, if we try using (Combined Cost) - (Separate Cost). isn't it ended up as Answer (B)
(x+7y) - (2x+6y) = x + 7y - 2x - 6y = -x+y which is a y-x
-> Combined, with a saving of y-x cents
I'm stuck here..
(x+7y) - (2x+6y) = x + 7y - 2x - 6y
It is the other way round as we are calculating saving You save 2x+6y And spend x+7y Therefore you save in total 2x+6y -(x +7y) = x-y _________________
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Re: To mail a package, the rate is x cents for the first pound [#permalink]
27 Jan 2012, 05:55
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miweekend wrote:
To mail a package, the rate is x cents for the first pound and y cents for each additional pound, where x>y. Two packages weighing 3 pounds and 5 pounds, respectively can be mailed seperately or combined as one package. Which method is cheaper and how much money is saved?
A. Combined, with a saving of x-y cents B. Combined, with a saving of y-x cents C. Combined, with a saving of x cents D. Separately, with a saving of x-y cents E. Separately, with a saving of y cents
If we ship two packages separately it'll cost: \(1x+2y\) for the 3 pounds package (x cents for the first pound and y cents for the additional 2 pounds) plus \(1x+4y\) for the 5 pounds package (x cents for the first pound and y cents for the additional 4 pounds), so total cost of shipping separately is \((x+2y)+(x+4y)=2x+6y\);
If we ship them together in one 8pound package it'll cost: \(1x+7y\) (x cents for the first pound and y cents for the additional 7 pounds);
Difference: \(Separately-Together=(2x+6y)-(x+7y)=x-y\) --> as given that \(x>y\) then this difference is positive, which makes shipping together cheaper by \(x-y\) cents.
Re: To mail a package, the rate is x cents for the first pound [#permalink]
03 Oct 2013, 07:25
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Re: To mail a package, the rate is x cents for the first pound [#permalink]
25 Jun 2015, 09:26
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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