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i know after seeing the solution u would say this question is a cake walk..but i have one confusion please help me wid it..

acc to GMAT , the figure is to scale, now can i assume this graph as a parabola ?? coz it looks to be a one...if it does then it can complicate the problem ....

on the graph above, when x = 1/2, y = 2; and x =1,y=1. The graph is symmetric with repsect to the vertical linke at x = 2. According to the graph, when x = 3, y = ?

i know this is a longer method..no doubt..but why doesn't it give the same answer...can anyone please explain it...

You can't assume the graph to be a parabola because it isn't one. And
even if it were: the y-value for x= 1/2 is only given to confuse us, so
don't use a formula and take the y-value for x=1 .

but i think i found my mistake this curve may be a fourth degree , sixth degree or any equation with even powers of X , since that is not clear so we cannot take it to be a "quadratic" equation.

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...