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Manager
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to scale or not ? [#permalink] New post 03 May 2006, 11:08
for this please refer to OG 11

PS , Q 7

i know after seeing the solution u would say this question is a cake walk..but i have one confusion please help me wid it..

acc to GMAT , the figure is to scale, now can i assume this graph as a parabola ?? coz it looks to be a one...if it does then it can complicate the problem ....
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 [#permalink] New post 03 May 2006, 11:49
I do not have OG 11. can you please post the question?
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 [#permalink] New post 03 May 2006, 13:00
PS Instructions say clearly, that figures are drawan as acurately as possible, unless otherwise stated.

So the points 1,0 i would assume it is.

because thats where the parabola intersects.
if you read the previous page the isntructions are there..
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 [#permalink] New post 03 May 2006, 14:13
Can one of you post the question, please?
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 [#permalink] New post 03 May 2006, 17:38
question is...

on the graph above, when x = 1/2, y = 2; and x =1,y=1. The graph is symmetric with repsect to the vertical linke at x = 2. According to the graph, when x = 3, y = ?
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 [#permalink] New post 04 May 2006, 01:17
ok we assume it to be a parabola then the eqn of graph can be taken as

Y= a x*x + b*x + c (i.e. the standard quadratic one..)

now i need to find a,b,c which is simple as

x=2 , y=0 as it appears from graph
x=1 , y=1 as given in question
x=.5 , y=2 as given in question

so from this i wud get a,b,c

now we need to find y when x=3 , put back in the equation we will get the value of y...

i know this is a longer method..no doubt..but why doesn't it give the same answer...can anyone please explain it...
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 [#permalink] New post 04 May 2006, 12:45
beyondinfinity wrote:
i know this is a longer method..no doubt..but why doesn't it give the same answer...can anyone please explain it...


You can't assume the graph to be a parabola because it isn't one. And
even if it were: the y-value for x= 1/2 is only given to confuse us, so
don't use a formula and take the y-value for x=1 .
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 [#permalink] New post 04 May 2006, 23:09
but i think i found my mistake this curve may be a fourth degree , sixth degree or any equation with even powers of X , since that is not clear so we cannot take it to be a "quadratic" equation.
  [#permalink] 04 May 2006, 23:09
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