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Today Jim is twice as old as Fred, and Sam is 2 years younge

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Today Jim is twice as old as Fred, and Sam is 2 years younge [#permalink] New post 12 Sep 2012, 02:44
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

93% (02:25) correct 7% (02:57) wrong based on 26 sessions
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Re: Today Jim is twice as old as Fred, and Sam is 2 years younge [#permalink] New post 12 Sep 2012, 02:52
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carcass wrote:
Today Jim is twice as old as Fred, and Sam is 2 years younger than Fred. Four years ago Jim was 4 times as old as Sam. How old is Jim now?

8
12
16
20
24


Today Jim is twice as old as Fred --> J=2F;
Today Sam is 2 years younger than Fred --> S+2=F;
Four years ago Jim was 4 times as old as Sam --> J-4=4*(S-4);

Substitute F: J=2(S+2) and J-4=4*(S-4) --> J=2S+4 and J=4S-12 --> subtract one from another 0=2S-16 --> S=8 --> J=2(S+2)=20.

Answer: D.
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Re: Today Jim is twice as old as Fred, and Sam is 2 years younge [#permalink] New post 12 Sep 2012, 03:14
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Re: Today Jim is twice as old as Fred, and Sam is 2 years younge [#permalink] New post 12 Sep 2012, 09:27
carcass wrote:
Today Jim is twice as old as Fred, and Sam is 2 years younger than Fred. Four years ago Jim was 4 times as old as Sam. How old is Jim now?

A. 8
B. 12
C. 16
D. 20
E. 24


Use of graphical presentation helps a lot in such age related questions. Let's see how it works.

----------4 yeas ago----------------------------today------------
-------J-------F--------S---------------------.J---------F---------S

----------------------------------------------(2x)--------(x)---------(x-2) [let's consider today age of Fred is x, the ages of Jim is 2x, and age of Sam is (x-2)]
------(2x-4)-----(x-4)-------(x-2-4)---------------------------------------[this are the ages of J, F and S 4 years ago]


As, per condition given in the question,
->2x-4= 4(x-6)
-> 2x-4=4x-24
-> 20=2x
-> x=10

Therefore, 2x=20, this is the age of Jim today.
So, the answer is D
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Re: Today Jim is twice as old as Fred, and Sam is 2 years younge [#permalink] New post 12 Sep 2012, 10:02
Expert's post
premnath wrote:
carcass wrote:
Today Jim is twice as old as Fred, and Sam is 2 years younger than Fred. Four years ago Jim was 4 times as old as Sam. How old is Jim now?

A. 8
B. 12
C. 16
D. 20
E. 24


Use of graphical presentation helps a lot in such age related questions. Let's see how it works.

----------4 yeas ago----------------------------today------------
-------J-------F--------S---------------------.J---------F---------S

----------------------------------------------(2x)--------(x)---------(x-2) [let's consider today age of Fred is x, the ages of Jim is 2x, and age of Sam is (x-2)]
------(2x-4)-----(x-4)-------(x-2-4)---------------------------------------[this are the ages of J, F and S 4 years ago]


As, per condition given in the question,
->2x-4= 4(x-6)
-> 2x-4=4x-24
-> 20=2x
-> x=10

Therefore, 2x=20, this is the age of Jim today.
So, the answer is D


is pretty nice your method, it depends what is more comnfortable for you.

For me is much faster in this scenario the algebric approach ;)
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Re: Today Jim is twice as old as Fred, and Sam is 2 years younge   [#permalink] 12 Sep 2012, 10:02
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