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Tom and Linda stand at point A. Linda begins to walk in a

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Senior Manager
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Tom and Linda stand at point A. Linda begins to walk in a [#permalink] New post 24 Jun 2007, 15:21
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Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?
60
72
84
90
108
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Re: PS: Walk away [#permalink] New post 24 Jun 2007, 16:02
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ArvGMAT wrote:
Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?
60
72
84
90
108


for half: (2n + 2)/2 = 6n; n = 12m minuets
for double: 2(2n + 2) = 6n; n = 120 minuets

diff = =108 minuets.
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 [#permalink] New post 24 Jun 2007, 20:54
very confusing language, but finally I understood what it meant. Is this a real GMAT question?
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Re: PS: Walk away [#permalink] New post 27 Jun 2007, 01:45
Himalayan wrote:
ArvGMAT wrote:
Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?
60
72
84
90
108


for half: (2n + 2)/2 = 6n; n = 12m minuets
for double: 2(2n + 2) = 6n; n = 120 minuets

diff = =108 minuets.


Himalyan, can you please explain your solution and show the steps that you take to arrive at those time times? Thanks.
Re: PS: Walk away   [#permalink] 27 Jun 2007, 01:45
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Tom and Linda stand at point A. Linda begins to walk in a

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