Tom, Jane, and Sue each purchased a new house. The average : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 18 Jan 2017, 14:28

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Tom, Jane, and Sue each purchased a new house. The average

Author Message
Manager
Joined: 10 Oct 2005
Posts: 61
Followers: 1

Kudos [?]: 0 [0], given: 0

Tom, Jane, and Sue each purchased a new house. The average [#permalink]

### Show Tags

10 Oct 2005, 21:03
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was $120,000. What was the median price of the three houses? (1) The price of Tomâ€™s house was$110,000.
(2) The price of Janeâ€™s house was \$120,000.
Senior Manager
Joined: 02 Oct 2005
Posts: 297
Followers: 1

Kudos [?]: 21 [0], given: 0

### Show Tags

10 Oct 2005, 21:32
Ans is C

Both combined together would give median (120,000)
Manager
Joined: 14 Apr 2003
Posts: 84
Followers: 1

Kudos [?]: 22 [0], given: 0

### Show Tags

10 Oct 2005, 21:32
We need both the statements to arrive at median.

Given only one price and average would only give us combined price of other two that can affect the median price.
Director
Joined: 21 Aug 2005
Posts: 793
Followers: 2

Kudos [?]: 24 [0], given: 0

### Show Tags

10 Oct 2005, 21:34
B

1. T=110K: J,S = 150,100 -> med T -or- J,S = 120,130-> med J
2. J=120K
=> T+S=120K,
Either T=K=S => med = 120 or T>J>S or T<J<S
In any case, median is 120K
Senior Manager
Joined: 02 Oct 2005
Posts: 297
Followers: 1

Kudos [?]: 21 [0], given: 0

### Show Tags

10 Oct 2005, 21:47
Oops. I fell for the trap. Thanks for correcting gsr.
Director
Joined: 15 Aug 2005
Posts: 798
Location: Singapore
Followers: 2

Kudos [?]: 55 [0], given: 0

### Show Tags

11 Oct 2005, 04:50
gsr wrote:
B

1. T=110K: J,S = 150,100 -> med T -or- J,S = 120,130-> med J
2. J=120K
=> T+S=120K,
Either T=K=S => med = 120 or T>J>S or T<J<S
In any case, median is 120K

Agree. B is sufficient to calculate the median. Good trap question.
_________________

Cheers, Rahul.

11 Oct 2005, 04:50
Display posts from previous: Sort by