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0.1+0.1^2+0.1^3=

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0.1+0.1^2+0.1^3= [#permalink] New post 13 Aug 2012, 05:59
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00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

90% (01:26) correct 10% (00:26) wrong based on 345 sessions
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Re: 01+01^2+0.1^3= [#permalink] New post 13 Aug 2012, 06:00
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Re: 01+01^2+0.1^3= [#permalink] New post 13 Aug 2012, 10:31
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Bunuel, I think the question is missing some decimal points.
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 14 Aug 2012, 15:20
I don't really like this question, since the answers seem to be taking rounding into account. The real answer is .111. So rounded to the hundredths its B, rounded to the tenths its A.
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 14 Aug 2012, 19:40
Bunuel,

You have a mistake in your question. Choice B should be (.111) and not (.11).

The equation in the solution can be simplified to (.1 + .01 + .001).

Adding those together you get:

.100
.010
.001
------
.111 - Which is answer choice (B)
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 14 Aug 2012, 22:20
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 15 Aug 2012, 03:58
Given 0.1+0.1^2+0.1^3
=>0.1(1+0.1+0.01)
=>0.1(1.11)
=>0.111
hence correct answer is B
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 15 Aug 2012, 09:05
0.1+0.01+0.001 = 0.111

Answer is B.
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 16 Aug 2012, 23:56
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Re: 0.1+0.1^2+0.1^3= [#permalink] New post 27 Feb 2014, 19:34
can be solved as:
1/10 + 1/100 + 1/1000

= (1+10+111) / 1000

= 0.111 = Answer = B
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Re: 0.1+0.1^2+0.1^3=   [#permalink] 27 Feb 2014, 19:34
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