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# 0.1+0.1^2+0.1^3=

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Math Expert
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13 Aug 2012, 05:59
Expert's post
3
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Difficulty:

5% (low)

Question Stats:

94% (01:27) correct 6% (00:32) wrong based on 1324 sessions

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0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

Practice Questions
Question: 17
Page: 154
Difficulty: 550
[Reveal] Spoiler: OA

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13 Aug 2012, 06:00
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SOLUTION

0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

$$0.1+0.1^2+0.1^3=0.1+0.01+0.001=0.111$$.

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13 Aug 2012, 10:31
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Bunuel, I think the question is missing some decimal points.
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14 Aug 2012, 15:20
I don't really like this question, since the answers seem to be taking rounding into account. The real answer is .111. So rounded to the hundredths its B, rounded to the tenths its A.
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14 Aug 2012, 19:40
Bunuel,

You have a mistake in your question. Choice B should be (.111) and not (.11).

The equation in the solution can be simplified to (.1 + .01 + .001).

.100
.010
.001
------
.111 - Which is answer choice (B)
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14 Aug 2012, 22:20
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15 Aug 2012, 03:58
Given 0.1+0.1^2+0.1^3
=>0.1(1+0.1+0.01)
=>0.1(1.11)
=>0.111
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15 Aug 2012, 09:05
0.1+0.01+0.001 = 0.111

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16 Aug 2012, 23:56
SOLUTION

0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

$$0.1+0.1^2+0.1^3=0.1+0.01+0.001=0.111$$.

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27 Feb 2014, 19:34
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can be solved as:

$$\frac{1}{10} +\frac{1}{100} + \frac{1}{1000}$$

$$=\frac{1+10+111}{1000}$$

= 0.111 = Answer = B
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Last edited by PareshGmat on 09 Sep 2014, 22:26, edited 1 time in total.
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09 Sep 2014, 22:16
Bunuel wrote:
0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

Practice Questions
Question: 17
Page: 154
Difficulty: 550

sometimes i get confused with doubling the decimal point so i will do in below way.

1/10 + 1/(10)^2 +1/(10)^3
=0.111
b
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06 Nov 2015, 18:38
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01 Dec 2016, 09:26
Hello from the GMAT Club BumpBot!

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01 Dec 2016, 09:57
Bunuel wrote:
0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

$$0.1+0.1^2+0.1^3$$

$$= \frac{1}{10} + \frac{1}{100} + \frac{1}{1000}$$

$$= 0.100 + 0.010 + 0.001$$

$$= 0.111$$

Hence, answer will be (B) $$= 0.111$$
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Re: 0.1+0.1^2+0.1^3=   [#permalink] 01 Dec 2016, 09:57
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