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0.1+0.1^2+0.1^3=

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New post 13 Aug 2012, 05:59
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New post 13 Aug 2012, 10:31
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Bunuel, I think the question is missing some decimal points.
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New post 14 Aug 2012, 15:20
I don't really like this question, since the answers seem to be taking rounding into account. The real answer is .111. So rounded to the hundredths its B, rounded to the tenths its A.
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New post 14 Aug 2012, 19:40
Bunuel,

You have a mistake in your question. Choice B should be (.111) and not (.11).

The equation in the solution can be simplified to (.1 + .01 + .001).

Adding those together you get:

.100
.010
.001
------
.111 - Which is answer choice (B)
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New post 15 Aug 2012, 03:58
Given 0.1+0.1^2+0.1^3
=>0.1(1+0.1+0.01)
=>0.1(1.11)
=>0.111
hence correct answer is B
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New post 15 Aug 2012, 09:05
0.1+0.01+0.001 = 0.111

Answer is B.
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New post 16 Aug 2012, 23:56
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New post 27 Feb 2014, 19:34
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can be solved as:

\(\frac{1}{10} +\frac{1}{100} + \frac{1}{1000}\)

\(=\frac{1+10+111}{1000}\)

= 0.111 = Answer = B
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Last edited by PareshGmat on 09 Sep 2014, 22:26, edited 1 time in total.
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New post 09 Sep 2014, 22:16
Bunuel wrote:
0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

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Question: 17
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sometimes i get confused with doubling the decimal point so i will do in below way.

1/10 + 1/(10)^2 +1/(10)^3
=0.111
b
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New post 01 Dec 2016, 09:26
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Re: 0.1+0.1^2+0.1^3= [#permalink]

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New post 01 Dec 2016, 09:57
Bunuel wrote:
0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3


\(0.1+0.1^2+0.1^3\)

\(= \frac{1}{10} + \frac{1}{100} + \frac{1}{1000}\)

\(= 0.100 + 0.010 + 0.001\)

\(= 0.111\)

Hence, answer will be (B) \(= 0.111\)
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Re: 0.1+0.1^2+0.1^3=   [#permalink] 01 Dec 2016, 09:57
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