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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
Given 0.1+0.1^2+0.1^3
=>0.1(1+0.1+0.01)
=>0.1(1.11)
=>0.111
hence correct answer is B
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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
0.1+0.01+0.001 = 0.111

Answer is B.
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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
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Bunuel wrote:
0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

Practice Questions
Question: 17
Page: 154
Difficulty: 550



sometimes i get confused with doubling the decimal point so i will do in below way.

1/10 + 1/(10)^2 +1/(10)^3
=0.111
b
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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
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Bunuel wrote:
0.1+0.1^2+0.1^3=

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3


\(0.1+0.1^2+0.1^3\)

\(= \frac{1}{10} + \frac{1}{100} + \frac{1}{1000}\)

\(= 0.100 + 0.010 + 0.001\)

\(= 0.111\)

Hence, answer will be (B) \(= 0.111\)
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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
Bunuel wrote:
\(0.1+0.1^2+0.1^3=\)

(A) 0.1
(B) 0.111
(C) 0.1221
(D) 0.2341
(E) 0.3

Practice Questions
Question: 17
Page: 154
Difficulty: 550


\(0.1+0.1^2+0.1^3=\)

\(0.1 + 0.01 + 0.001\)

\(0.111\)

(A)
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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
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Re: 0.1 + 0.1^2 + 0.1^3 = [#permalink]
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