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what is the total 4 digit numbers that can be formed using the digits 0 to 5 without repetition , such that number is divisible by 9? _________________

we have two patterns: \(3, 4, 2, 0\) \(5, 3, 1, 0\) \(0\) can't be on the first place.

For the first place we choose among 3 digits, for the second among three digits (now we can use zero) as well, for the third between 2 digits, for the fourth - 1. \(3*3*2*1=18 18*2=36\)

gmatclubot

Re: total number of 4 digits
[#permalink]
20 Jun 2011, 10:55

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