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Tough and tricky 2:

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Tough and tricky 2: [#permalink] New post 11 Oct 2009, 17:17
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Tough and tricky 2:

2. The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is $5.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of \sqrt{2}*x-x cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat?

(A) $4.50
(B) $5.10
(C) $5.30
(D) $5.50
(E) $5.60
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Re: Tough and tricky 2: [#permalink] New post 12 Oct 2009, 04:18
320 + 5x = 580 - (1.414 - 1)x

Solve to get x
Answer = (320 + 5x)/100
= 5.6
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Re: Tough and tricky 2: [#permalink] New post 12 Oct 2009, 09:44
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Re: Tough and tricky 2: [#permalink] New post 03 May 2011, 23:51
5.6 indeed.solving for xd and then substituting back to 3.2 + 5x gives the value.
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Re: Tough and tricky 2: [#permalink] New post 02 Dec 2012, 23:07
3.20 + 5xD = 5.80 - (\sqrt{2}x - x)D
3.2 + 5xD = 5.80 - \sqrt{2}xD + xD
xD = \frac{2.6}{4+\sqrt{2}}
xD = 0.49

The price: 3.2 + 5 (.49) = 5.65

Answer: 5.6
Re: Tough and tricky 2:   [#permalink] 02 Dec 2012, 23:07
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