Tough one : GMAT Quantitative Section
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# Tough one

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Intern
Joined: 01 Nov 2010
Posts: 38
Location: India
Schools: Tuck, Kellogg, Tepper
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Tough one [#permalink]

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17 Jun 2011, 08:56
if f(x)>0 and f(x+y)=f(x)f(y) for all x,y. Then f(2) =?
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Status: 700 (q47,v40); AWA 6.0
Joined: 16 Mar 2011
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GMAT 1: 700 Q47 V40
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Re: Tough one [#permalink]

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17 Jun 2011, 09:34
Quite a vague question but the best extent of information I can draw from this one is that f(0) = 1 and f(n) = f(1)^n

What is the source by the way?

Regards
Rahul
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Regards
Rahul

Veritas Prep GMAT Instructor
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Re: Tough one [#permalink]

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18 Jun 2011, 06:40
passion4ivymba wrote:
if f(x)>0 and f(x+y)=f(x)f(y) for all x,y. Then f(2) =?

Some information is missing here.
You get $$f(0+0) = f(0)^2$$
$$f(0)[f(0) - 1] = 0$$
$$f(0) = 1$$

Then, you get infinite GPs each having a different value for f(2) depending on what value you choose for f(1).
Say f(1) = 2
... f(-3) = 1/8, f(-2) = 1/4, f(-1) = 1/2, f(0) = 1, f(1) = 2, f(2) = 4, f(3) = 8 and so on

Say f(1) = 3
...f(-3) = 1/27, f(-2) = 1/9, f(-1) = 1/3, f(0) = 1, f(1) = 3, f(2) = 9, f(3) = 27 and so on
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Karishma
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Intern Joined: 01 Nov 2010 Posts: 38 Location: India Schools: Tuck, Kellogg, Tepper Followers: 0 Kudos [?]: 4 [0], given: 3 Re: Tough one [#permalink] ### Show Tags 18 Jun 2011, 09:14 Following are the answer options... rt2 1 0 -1 -rt2 Intern Joined: 01 Nov 2010 Posts: 38 Location: India Schools: Tuck, Kellogg, Tepper Followers: 0 Kudos [?]: 4 [0], given: 3 Re: Tough one [#permalink] ### Show Tags 18 Jun 2011, 09:15 Thanks for the explaination..... VeritasPrepKarishma wrote: passion4ivymba wrote: if f(x)>0 and f(x+y)=f(x)f(y) for all x,y. Then f(2) =? Some information is missing here. You get $$f(0+0) = f(0)^2$$ $$f(0)[f(0) - 1] = 0$$ $$f(0) = 1$$ Then, you get infinite GPs each having a different value for f(2) depending on what value you choose for f(1). Say f(1) = 2 ... f(-3) = 1/8, f(-2) = 1/4, f(-1) = 1/2, f(0) = 1, f(1) = 2, f(2) = 4, f(3) = 8 and so on Say f(1) = 3 ...f(-3) = 1/27, f(-2) = 1/9, f(-1) = 1/3, f(0) = 1, f(1) = 3, f(2) = 9, f(3) = 27 and so on Re: Tough one [#permalink] 18 Jun 2011, 09:15 Similar topics Replies Last post Similar Topics: 1 Addition Question_Tough 1 04 Dec 2011, 20:40 40 Two guns were fired from the same place at an interval of 10 14 06 May 2010, 04:34 2 A portion of$6600 is invested at a 5% annual return, while the remain 6 15 Apr 2010, 15:50
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# Tough one

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