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can someone pls solve n explain these problems?
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The area is 18
AD = 10
AE =5
CD=4
CE=3
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Before calculate you should establish why those triangles are equal.
In Ds it may hurt you doing otherwise.
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wait! first lemme get it straight, what is the area of that quad? l*b right
celix if u tellin area = 18 ==> AB*BC =6*3 , but since as per ur solution if cd=4 then cb =4 and then area will be 6*4 ...
where am i going wrong, please explain
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1. 18
Triangle ABD and triangle ECD are similar triangles (share the same angle)
Hence EC = 3 (3,4,5 triangle)
Also triangle AEF and ECD are similar triangles, since they are formed by parallel lines cut by a line (transversal as math geeks would call it)
Infact these traingles are equal since AE = ED = 5
Area of the quadrilateral = 1/2 (4) (3+6) = 18
2. C (It will not pass), assuming that each of the L's vote YES on the bill, Otherwise it is E.
From #1 we get total L's who vote = (55/100)*400*(85/100) = 187 (But we don't know about Rs and Ds.
From #2 we know that none of the Rs or Ds vote.
Hence total votes = 187 < 189. Hence C. (or E if we don't know each one will vote YES or NO)
3. 11 (div by 78) + 9 (div by 91) = 20.
78*10 = 780 (including 78 there are 10 numbers. Excluding 78 there are 9 of them)
78+78*2 = 936 < 1000. So 2 more available.
Hence No divisible by 78 =9+2 = 11
Similarly for 91 there are 10-1 = 9
Total = 20.
OA's please?
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Approximation is very fast for the third question
xxx is a multiple of either 78 or 91
You see 10*78 + 2*78 = 936
So there are 11 multiples of 78
Similiary for 91:
10*91=91
So there are 9 multples of 91
Next step are there multiples counted twice?
91= 7*13
78= 2*3*13
Both are equal if 2*3 and 7 have a common multiple, wich is 7 and 6 respectively. Notice that above you needn't to look out for common multiples above 999.
So 7*2*3*13=546, or 6*7*13 is counted twice
So 19 is the answer
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giddi77 wrote: 1. 18
Triangle ABD and triangle ECD are similar triangles (share the same angle) Hence EC = 3 (3,4,5 triangle)
Also triangle AEF and ECD are similar triangles, since they are formed by parallel lines cut by a line (transversal as math geeks would call it)
Infact these traingles are equal since AE = ED = 5
Area of the quadrilateral = 1/2 (4) (3+6) = 18
2. C (It will not pass), assuming that each of the L's vote YES on the bill, Otherwise it is E.
From #1 we get total L's who vote = (55/100)*400*(85/100) = 187 (But we don't know about Rs and Ds. From #2 we know that none of the Rs or Ds vote.
Hence total votes = 187 < 189. Hence C. (or E if we don't know each one will vote YES or NO)
3. 11 (div by 78) + 9 (div by 91) = 20.
78*10 = 780 (including 78 there are 10 numbers. Excluding 78 there are 9 of them) 78+78*2 = 936 < 1000. So 2 more available.
Hence No divisible by 78 =9+2 = 11 Similarly for 91 there are 10-1 = 9
Total = 20.
OA's please?
 u nailed them all , can u please explain the 3rd
how did u come to this conclusion ( i know its very silly) i am not able to understand it.
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Are you sure it's 20?
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allabout wrote:
Next step are there multiples counted twice?
91= 7*13 78= 2*3*13
Both are equal if 2*3 and 7 have a common multiple, wich is 7 and 6 respectively. Notice that above you needn't to look out for common multiples above 999.
So 7*2*3*13=546, or 6*7*13 is counted twice
So 19 is the answer
Tooo good allabout! Thanks for explaining it very clearly! I'll remember this.
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razrulz wrote: wait! first lemme get it straight, what is the area of that quad? l*b right
celix if u tellin area = 18 ==> AB*BC =6*3 , but since as per ur solution if cd=4 then cb =4 and then area will be 6*4 ...
where am i going wrong, please explain
The area = (AB+CE)*BC/2
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Senior Manager
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hey all about, i got this question from a grp! someone had posted the questions and answers and asked for explanations. by far , her answer for the 3rd question was 20 , so i am not sure !
so i dont have a OA. I am sorry!
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razrulz wrote: hey all about, i got this question from a grp! someone had posted the questions and answers and asked for explanations. by far , her answer for the 3rd question was 20 , so i am not sure !
so i dont have a OA. I am sorry!
Ok, the question may be ambiguous, since "different numbers" is omitted.
Generally 546 is one number, so the answer is 19 not 20.
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Senior Manager
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allabout wrote: razrulz wrote: hey all about, i got this question from a grp! someone had posted the questions and answers and asked for explanations. by far , her answer for the 3rd question was 20 , so i am not sure !
so i dont have a OA. I am sorry! Ok, the question may be ambiguous, since "different numbers" is omitted. Generally 546 is one number, so the answer is 19 not 20.
AYE AYE SIR !  thnks again
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According to me the two possible answers are 18 and 22.5. Since 18 is the only one given it should be it.
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