Train A leaves the station traveling at 30 miles per hour.

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Train A leaves the station traveling at 30 miles per hour. [#permalink]

09 Feb 2011, 15:16

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36. Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 40 miles per hour. How far from the station was train A overtaken by train B?
(A) 180
(B) 240
(C) 270
(D) 300
(E) 320

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Re: Train A leaves the station traveling at 30 miles per hour. [#permalink]

09 Feb 2011, 18:56

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loveparis wrote:

This question tests you on relative speed.
Train A leaves the station traveling at 30 miles/hr. So it covers 30*2 = 60 miles in 2 hrs. After 2 hrs, train B leaves the station. When train B leaves the station, distance between train A and train B is 60 miles since train A has already traveled 60 miles.
Now train B needs to cover up this distance between them by traveling faster than train A. In one hour, train B covers 10 miles more than train A (because train B's speed is 10 miles/hr more than train A's speed). So train B will cover the extra 60 miles in 6 hours.
Train A had traveled for 2 + 6 = 8 hrs before it was overtaken by train B. Hence, it had covered a distance of 8*30 = 240 miles.
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Re: Train A leaves the station traveling at 30 miles per hour. [#permalink]

09 Feb 2011, 17:03

When train B catches train A, their location will be the same, and since they left the same point, their distance traveled will be the same.

RT = RT

30mph(T+2) = 40mph(T)

Solve for T. They meet after 6 hours. Plug 6 into either equation and get 240 miles

Re: Train A leaves the station traveling at 30 miles per hour. [#permalink] 09 Feb 2011, 17:03

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Train A leaves the station traveling at 30 miles per hour.

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