Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Train T leaves from town A for town B and travels at a [#permalink]
15 Oct 2006, 11:59

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 1 sessions

Train T leaves from town A for town B and travels at a constant speed of x mph. Train S leaves town B for town A, later than the train T, and also travels at a constant speed of y mph. Will they meet closer to A or to B?

1) y>x
2) They finished their trips at the same time

Train T leaves from town A for town B and travels at a constant speed of x mph. Train S leaves town B for town A, later than the train T, and also travels at a constant speed of y mph. Will they meet closer to A or to B?

1) y>x
2) They finished their trips at the same time

ONE

INSUFF ...WE NEED TO KNOW THE TIME LAPSED BETWEEN BOTH TRAINS LEAVING THE STATIONS
2) IF THEY REACHED THE SAME DITINATION AT THE SAME TIME

Train T leaves from town A for town B and travels at a constant speed of x mph. Train S leaves town B for town A, later than the train T, and also travels at a constant speed of y mph. Will they meet closer to A or to B?

1) y>x
2) They finished their trips at the same time

I would say E as well

Since we don't know how much later train S leaves than train T.

(2) is sufficient, best way to see it is by drawing it on paper. We know that both trains finish their trips at the same time, so we know y>x

If we cut the distance in half, train S will be in the middle and, regardless of how much slower train T is, it will always be a little bit closer to B, therefore they meet closer to town B

By using both statements, I can think of situations which produce both answers.

Since we don't know how long train S waits to leave or how fast either of them go, train S could leave either before S gets to the halfway point, or after train S gets to the halfway point.

If train S waits to leave until train T has reached the halfway point, then they meet closer to B. If train S leaves only shortly after train T and travels much faster, then train S could pass the midway point of the track before train T does.

If train S leaves later than T, but finishes at the same time, then T is traveling faster than S.
So, when they meet, the distance between the meeting point and B should be smaller than the distance between the meeting point and A. So, statement 2 is SUFF

If train S leaves later than T, but finishes at the same time, then T is traveling faster than S. So, when they meet, the distance between the meeting point and B should be smaller than the distance between the meeting point and A. So, statement 2 is SUFF

IF If train S leaves later than T, but finishes at the same time, then S is traveling faster than T and not vice versa..Can you pls. explain in little detail that how is it (B) ..and what is the OA ?

If train S leaves later than T, but finishes at the same time, then T is traveling faster than S. So, when they meet, the distance between the meeting point and B should be smaller than the distance between the meeting point and A. So, statement 2 is SUFF

Anand, What if the difference in rates is negligible and the difference in time is huge???

Without actual numbers, its hard to decide on the meeting point. It can fall in either of the halves, depending on the difference in rates and difference in time.

two extreme examples
d=100
trains S =10, then T=10h
Train T :y=100 then T=1h

they meet closer to B
or
d=120
x=10, then T=12h
y=10,1 then T=11,88h

they meet closer to B
since right after T=6h
S is closer to B
and
T has not crossed the mid distance yet since it left 0,12h late... and it will cross the mid point at 0.12h+ 11,88/2=5,94+,12=6,16h
hope it helps _________________

Great to know you are joining Kellogg. A lot was being talked about your last minute interview on Pagalguy (all good though). It was kinda surprise that you got the...

This is a long overdue post! A lot of Indian applicants, having scheduled interviews in March, reached out to me asking about my interview experience with Kellogg. I had a...

A critical phase of the MBA application, concurrent to researching your target schools, is “researching yourself” and building your profile. What are your unique traits? Where do you want to be...