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Traingles

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Traingles [#permalink] New post 28 Sep 2011, 13:37
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

25% (00:00) correct 75% (01:03) wrong based on 4 sessions
if two sides of the triangle are 12 and 8,then which of the following could be the area of the traingle

I 35
II 48
III 56

A. I only
B I and II
c .I and III
d. II and III
e I II and III

Guys need the explanation also.....
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Re: Traingles [#permalink] New post 28 Sep 2011, 14:19
Are you sure its "Area" they are asking for and not "Perimeter"?
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Re: Traingles [#permalink] New post 28 Sep 2011, 23:17
I also feel the same that it should be perimeter and not area.

But I also feel that this post should have been posted in the Quants section and not in the GMAT Experience section :)

BR
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Re: Traingles [#permalink] New post 29 Sep 2011, 02:48
IMO, I and II only..
Wats the OA?
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Re: Traingles [#permalink] New post 29 Sep 2011, 06:10
ya the question is for area and not the perimeter.....

Sorry for posting in the wrong section..
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Re: Traingles [#permalink] New post 29 Sep 2011, 06:28
Ans : B
i and ii only.
the max area can be 48 or less. So it is 35 or 48
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Re: Traingles [#permalink] New post 29 Sep 2011, 09:04
I also feel that it should be I and II.
What's the OA??
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Re: Traingles [#permalink] New post 29 Sep 2011, 16:14
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Area is fine.

Max area is 12*8/2 = 248. so anything equal or under 48 can be the area.
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Re: Traingles [#permalink] New post 29 Sep 2011, 17:29
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area of the triangle with two known side lengths a , b = (1/2)(a*b)*sin(a,b)

(a,b) is the angle between sides a and b


area = (1/2)*8*12*sin(a,b) = 48 sin(a,b)

sin(a,b) is always between 0 and 1 inclusive. (as thats the sin range)

=> area = 48*[0,..1]

=>0<=area <=48

I and II are only possible options that satisfy the above condition.

Answer is B.
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Re: Traingles [#permalink] New post 30 Sep 2011, 13:42
please explain?

how you come up with max area of 48.

thanks .
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Re: Traingles [#permalink] New post 30 Sep 2011, 17:55
area = (1/2)*8*12*sin(a,b) = 48 sin(a,b)

maximum value of sin angle is 1. so maximum value of area in the above statement = 48*1= 48

yourpal wrote:
please explain?

how you come up with max area of 48.

thanks .
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Re: Traingles [#permalink] New post 01 Oct 2011, 01:04
Agreed the max area is 1/2 * 12 * 8 * sin@ and max value of sin@ is 1 = 48
B is the answer.
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http://gmatclub.com/forum/massive-collection-of-verbal-questions-sc-rc-and-cr-106195.html#p832142
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http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html
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Re: Traingles   [#permalink] 01 Oct 2011, 01:04
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