Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
0% (00:00) correct
0% (00:00) wrong based on 0 sessions
It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?
A. z(y – x)/x + y
B. z(x – y)/x + y
C. z(x + y)/y – x
D. xy(x – y)/x + y
E. xy(y – x)/x + y
I followed this approach: Since trains are approaching each other, relative speed =x+y Let t be the time taken then t= z/(x+y)
Now distance travelled by high speed train = t*x=zx/(x+y)
distance travelled by average speed train = t*y=zy/(x+y)