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# travel agent offers

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Senior Manager
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23 Sep 2010, 13:51
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Question Stats:

67% (03:37) correct 33% (01:20) wrong based on 9 sessions

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A travel agent offers a vacation plan which costs x dollars for the first day, and x/6 for each additional day.
How much does a vacation of y days cost, where y > 1.

yz/6
yz/3
(yz+6z)/6
(yz+5z)/6
(y2z+5yz+z2)/3

According to me it has to be C, but OA is different.
Its from Kaplan 800
[Reveal] Spoiler: OA

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23 Sep 2010, 13:54
onedayill wrote:
A travel agent offers a vacation plan which costs x dollars for the first day, and x/6 for each additional day.
How much does a vacation of y days cost, where y > 1.

yz/6
yz/3
(yz+6z)/6
(yz+5z)/6
(y2z+5yz+z2)/3

According to me it has to be C, but OA is different.
Its from Kaplan 800

Cost = x + (y-1)*x/6 = (6x + (y - 1)*x)/6 = (yx+5x)/6

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23 Sep 2010, 14:01
shrouded1 wrote:
onedayill wrote:
A travel agent offers a vacation plan which costs x dollars for the first day, and x/6 for each additional day.
How much does a vacation of y days cost, where y > 1.

yz/6
yz/3
(yz+6z)/6
(yz+5z)/6
(y2z+5yz+z2)/3

According to me it has to be C, but OA is different.
Its from Kaplan 800

Cost = x + (y-1)*x/6 = (6x + (y - 1)*x)/6 = (yx+5x)/6

Come on...
A blunder mistake from my side.

I was considering y in following equation instead of y-1

(6x + (y - 1)*x)/6
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23 Sep 2010, 14:05
onedayill wrote:
Come on...
A blunder mistake from my side.

I was considering y in following equation instead of y-1

(6x + (y - 1)*x)/6

Ha, I am not judging !
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23 Sep 2010, 15:19
Cost of first day: $$x$$
Cost of each add'l day: $$\frac{x}{6}$$
Number of add'l days: $$y-1$$

Total cost = $$x + [(y-1) * \frac{x}{6}]$$

$$x + \frac{xy - x}{6}$$

$$\frac{6x}{6} + \frac{xy-x}{6}$$

$$\frac{xy + 5x}{6}$$

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23 Sep 2010, 18:17
IMO D. I was initially confused by seeing 'z' in answer choice.
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23 Sep 2010, 22:43
+1 D

That "z" was tricky hehe. At the begining I thought "that's a 800 question!" LOL.
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23 Sep 2010, 23:13
(yz+6z)/6 is the ans :

Lets say 2 days travelled => y = 2
and lets say first day charged $6 and the 2nd day the amount would be x/6 =>$6/6 = $1 So, for the 2(Y) days, he/she suppoed to pay$6 ( 1st Day charge)+ \$1 (2nd charge) = 7

now substitute the values for y = 2 and x= 6 ( In this case, x value = z value )
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24 Sep 2010, 05:24
metallicafan wrote:
+1 D

That "z" was tricky hehe. At the begining I thought "that's a 800 question!" LOL.

Sorry for the confusion...
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Re: travel agent offers   [#permalink] 24 Sep 2010, 05:24
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