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travel agent offers [#permalink] New post 23 Sep 2010, 14:51
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Question Stats:

80% (04:53) correct 20% (04:00) wrong based on 0 sessions
A travel agent offers a vacation plan which costs x dollars for the first day, and x/6 for each additional day.
How much does a vacation of y days cost, where y > 1.

yz/6
yz/3
(yz+6z)/6
(yz+5z)/6
(y2z+5yz+z2)/3


According to me it has to be C, but OA is different.
Its from Kaplan 800
[Reveal] Spoiler: OA

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Re: travel agent offers [#permalink] New post 23 Sep 2010, 14:54
onedayill wrote:
A travel agent offers a vacation plan which costs x dollars for the first day, and x/6 for each additional day.
How much does a vacation of y days cost, where y > 1.

yz/6
yz/3
(yz+6z)/6
(yz+5z)/6
(y2z+5yz+z2)/3


According to me it has to be C, but OA is different.
Its from Kaplan 800


Cost = x + (y-1)*x/6 = (6x + (y - 1)*x)/6 = (yx+5x)/6

Answer is D
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Re: travel agent offers [#permalink] New post 23 Sep 2010, 15:01
shrouded1 wrote:
onedayill wrote:
A travel agent offers a vacation plan which costs x dollars for the first day, and x/6 for each additional day.
How much does a vacation of y days cost, where y > 1.

yz/6
yz/3
(yz+6z)/6
(yz+5z)/6
(y2z+5yz+z2)/3


According to me it has to be C, but OA is different.
Its from Kaplan 800


Cost = x + (y-1)*x/6 = (6x + (y - 1)*x)/6 = (yx+5x)/6

Answer is D


Come on...
A blunder mistake from my side.

I was considering y in following equation instead of y-1

(6x + (y - 1)*x)/6
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Re: travel agent offers [#permalink] New post 23 Sep 2010, 15:05
onedayill wrote:
Come on...
A blunder mistake from my side.

I was considering y in following equation instead of y-1

(6x + (y - 1)*x)/6



Ha, I am not judging ! :roll:
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Re: travel agent offers [#permalink] New post 23 Sep 2010, 16:19
Cost of first day: x
Cost of each add'l day: \frac{x}{6}
Number of add'l days: y-1

Total cost = x + [(y-1) * \frac{x}{6}]

Now simplify to find your answer:

x + \frac{xy - x}{6}

\frac{6x}{6} + \frac{xy-x}{6}

\frac{xy + 5x}{6}

Answer is D
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Re: travel agent offers [#permalink] New post 23 Sep 2010, 19:17
IMO D. I was initially confused by seeing 'z' in answer choice.
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Re: travel agent offers [#permalink] New post 23 Sep 2010, 23:43
+1 D

That "z" was tricky hehe. At the begining I thought "that's a 800 question!" LOL.
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Re: travel agent offers [#permalink] New post 24 Sep 2010, 00:13
(yz+6z)/6 is the ans :

Lets say 2 days travelled => y = 2
and lets say first day charged $6 and the 2nd day the amount would be x/6 =>$6/6 = $1
So, for the 2(Y) days, he/she suppoed to pay $6 ( 1st Day charge)+ $1 (2nd charge) = 7

now substitute the values for y = 2 and x= 6 ( In this case, x value = z value )
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Re: travel agent offers [#permalink] New post 24 Sep 2010, 06:24
metallicafan wrote:
+1 D

That "z" was tricky hehe. At the begining I thought "that's a 800 question!" LOL.


Sorry for the confusion...
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Re: travel agent offers   [#permalink] 24 Sep 2010, 06:24
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